我是Java编程的新手!所以试图解决问题,找到句子中最短,最长的单词。我的程序如下所示。我希望你的人能告诉我关于我的计划的正确方向 -
public class StringProblems {
void shortAndLongWord(String str) {
String sw = "", lw = "";
int s = str.length(), l = 0;
String words[] = str.split(" ");
for(String word:words) {
if(word.length()<s)
sw = word;
else if(word.length()>l)
lw = word;
}
System.out.println("LONGEST WORD : "+lw);
System.out.println("SHORTEST WORD : "+sw);
}
public static void main(String[] args) {
Scanner scr = new Scanner(System.in);
StringProblems obj = new StringProblems();
System.out.printf("Enter a line to get shortest and longest word:");
String str = scr.nextLine();
str += " ";
obj.shortAndLongWord(str);
}
}
此计划的输出是: *输入一行以获得最短和最快的词:这是句子
最长的词: 最简单的词:句子**
我不知道我的逻辑出错了!请帮帮我解决!
答案 0 :(得分:3)
您必须不断更新当前最短且最长的单词的长度:
public class StringProblems {
void shortAndLongWord(String str)
{
if (str == null)
return;
String sw="",lw="";
int s=str.length(),l=0;
String words[]=str.split(" ");
for(String word:words)
{
if(word.length()<s)
{
sw=word;
s = word.length();
}
if(word.length()>l)
{
lw=word;
l = word.length();
}
}
System.out.println("LONGEST WORD : "+lw);
System.out.println("SHORTEST WORD : "+sw);
}
public static void main(String[] args) {
Scanner scr=new Scanner(System.in);
StringProblems obj=new StringProblems();
System.out.printf("Enter a line to get shortest and longest word:");
String str=scr.nextLine();
str+=" ";
obj.shortAndLongWord(str);
}
}
答案 1 :(得分:2)
您需要不断更新l
(最长字的长度)和s
(最小字的长度)
if(word.length()<s)
{
sw=word;
s = word.length();
}
if(word.length()>l)
{
lw=word;
l = word.length();
}
此外,您还需要处理边界条件。 例如,如果字符串是单个单词会发生什么。当输入字符串为null等时会发生什么。
答案 2 :(得分:0)
在迭代期间,您没有更新l
和s
的值。你应该尝试这样的事情:
if (word.length() < s) {
sw = word;
s = word.length();
} else if (word.length() > l) {
lw = word;
l = word.length();
}
答案 3 :(得分:0)
import java.util.Scanner;
public class ShortestAndLongestWordInALine {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter any sentence : ");
String line = sc.nextLine();
sc.close();
int shortestWordLength = 0;
int longestWordLength = 0;
String shortestWord = "";
String longestWord = "";
int tempLength = 0;
String[] eachWordArray = line.split(" ");
boolean firstTime = false;
for (String eachWord : eachWordArray) {
tempLength = eachWord.length();
if (firstTime == false) {
firstTime = true;
shortestWordLength = tempLength;
shortestWord = eachWord;
longestWordLength = tempLength;
longestWord = eachWord;
}
if (tempLength > 0) {
if (tempLength < shortestWordLength) {
shortestWordLength = tempLength;
shortestWord = eachWord;
} else if (tempLength > longestWordLength) {
longestWordLength = tempLength;
longestWord = eachWord;
}
}
}
System.out.println("shortestWordLength = " + shortestWordLength + " shortestWord = " + shortestWord);
System.out.println("longestWordLength = " + longestWordLength + " longestWord = " + longestWord);
}
}
答案 4 :(得分:-1)
import java.util.*;
class lw
{
public static void main()
{
Scanner in=new Scanner(System.in);
String z=" ",lw="";
int q=0,o=0;
System.out.println("Enter string");
String str=in.nextLine()+" ";
int l=str.length();
for(int i=1;i<l;i++)
{
char ch=str.charAt(i);
if(ch!=' ')
z=z+ch;
else
{
q=z.length();
if(q>o)
lw=z;
o=q;
z="";
}
}
System.out.println("lw= "+lw);
System.out.println("length="+q);
}
}