如何在php中解析mysql中的空间数据

时间:2014-08-13 12:35:36

标签: php mysql json geospatial

我正在尝试将mysql中的空间数据结果转换为json格式,并且我得到相同线串的输出:

`[[-105.00341892242432, 39.75383843460583],[-105.0008225440979, 39.751891803969535]] `

但我需要得到这个:

`[{" coordinates":[[-105.00341892242432, 39.75383843460583], [-105.0008225440979, 39.751891803969535]]}`

有人可以帮我吗?

以下是代码:

    <?php

require_once("caroom_db.php");

header("Content-Type: application/json");
    //$l1 = '';
    $ll1 = array();
    //$lt = array();

 $json_response = array();

       $ll =0;
    //echo $l;
    $jsonData = '[';
    $num_point="SELECT NumPoints(geo_type) FROM line_park WHERE id='2'";
    $query = mysqli_query($cn, $num_point) or die (mysqli_error($cn)); 

    while ($row = mysqli_fetch_array($query, MYSQLI_ASSOC)) {


                    $ll  = $row["NumPoints(geo_type)"];
//echo $ll;
}

    for ($i=1; $i<=$ll; $i++) {

    $l1="SELECT X(PointN(geo_type,$i)), Y(PointN(geo_type,$i)) FROM line_park";



            $query = mysqli_query($cn, $l1) or die (mysqli_error($cn)); 
            while ($row = mysqli_fetch_array($query, MYSQLI_ASSOC)) {

        $ll1[0] = $row["X(PointN(geo_type,$i))"];
        $ll1[1] = $row["Y(PointN(geo_type,$i))"];


                array_push($json_response,$ll1);


            }


        }

        echo json_encode($json_response);

fclose($cn);


?>

提前谢谢!

2 个答案:

答案 0 :(得分:1)

好的,因为我的评论解决了您的问题,我将其作为答案发布,以便您接受。尝试使用php.net/manual/en/function.json-encode.php将数组转换为json,将数值推入数组会更简单。

要添加coodrinates,只需执行字符串连接

$jsonData = json_encode($json_response);
$jsonData = '{"coordinates":' . $jsonData . '}';

答案 1 :(得分:0)

使用另一个数组键。例如,

json_encode(array('coordinates' => $response));