Question

考虑范围数组：

 a = [[[4251, 4254], [4123, 4290]], [[4323, 4222], [4111, 4900]]]

另一个一维数组：

  b = [1324, 2745]

我想通过将数组b的第一个元素添加到数组a中的所有第一组范围来创建一个新数组，并将数组b的第二个元素添加到所有第二个元素数组a中的范围集，即

 [[[4251+1324, 4254+1324], [4123+1324, 4290+1324]], [[4323+2745, 4222+2745], [4111+2745, 4900+2745]]]

我怎样才能用Python做到这一点？

Answer 1

这应该适用于任何长度（提供a和b具有相同的长度）

[[[i+b[k],j+b[k]] for (i,j) in a[k]] for k in range(len(a))]

在你的情况下：

>>> pprint([[[i+b[k],j+b[k]] for (i,j) in a[k]] for k in range(len(a))])
[[[7880.1484209792943, 8171.6175205036743],
  [8225.6716915199249, 8378.3978601695999],
  [4729.0665464257172, 4732.276168393144],
  [5501.1899887058553, 5722.1839186014013],
  [360.55565340157807, 365.04589505745309],
  [20983.0, 20983.0],
  [217.14888548659997, 232.6226734478],
  [385.14888548659997, 400.62267344780003],
  [2823.2942485733347, 2840.4346062020377],
  [4502.0794526850004, 4700.9945330295996],
  [10417.852743984931, 10986.246567556096],
  [8191.6238503034892, 8194.8209578124479],
  [29570.28005012768, 29570.662880091983]],
 [[3250.5273987094843, 3252.7610916503263],
  [5593.4838299153871, 5596.0104208719731],
  [576.2276993911745, 622.11755144656183],
  [3188.3893120098983, 3206.7951214629902],
  [3246.2448304681798, 3250.0964343653186],
  [3272.9341862125516, 3274.8892802899418],
  [5969.1472437958755, 5971.2996518169357],
  [4255.3500559453041, 4258.126659789853]]]

Answer 2

这可以使用python中的list comprehension来实现。

a = [[1,2],[2,3],[3,4]]
b = [5,9]


[(x[0]+b[0], x[1]+b[1]) for x in a]

解释

for x in a - 对列表a进行迭代 x[0] - 子列表的第一个元素
x[0]+b[0] - 使用a中的第一个元素添加b中每个元素的第一个元素 x[1]+b[1] - 将a中每个元素的第二个元素添加到b

中的第二个元素

输出

[(6, 11), (7, 12), (8, 13)]

Answer 3

您可以使用列表理解：

对a[0]进行迭代，并为每组值添加b[0]和b[1]。

new_array = [(value[0] + b[0], value[1] + b[1]) for value in a[0]]

输出：

[(9202.148420979294, 10914.617520503674), (9547.671691519925, 11121.3978601696), (6051.066546425717, 7475.276168393144), (6823.189988705855, 8465.1839186014), (1682.5556534015782, 3108.045895057453), (22305.0, 23726.0), (1539.1488854866, 2975.6226734478), (1707.1488854866, 3143.6226734478), (4145.294248573335, 5583.434606202038), (5824.079452685, 7443.9945330296), (11739.852743984931, 13729.246567556096), (9513.62385030349, 10937.820957812448), (30892.28005012768, 32313.662880091983)]

Answer 4

一个。您可以像这样迭代a元素，但这会自行更改元素

for ind in range(len(a)):
    a[ind][0] += b[0]
    a[ind][1] += b[1]

B中。您可以使用列表推导：

c = [[item[0] + b[0], item[1] + b[1]] for item in a]

℃。您可以使用map：

c = map(lambda x: [x[0] + b[0], x[1] + b[1]], a)

Answer 5

使用numpy

>>>import numpy as np
>>>a =np.array( [[4251, 4254], [4123, 4290], [4323, 4222], [4111, 4900]])
>>>b =np.array([1324, 2745])
>>>a+b


array([[5575, 6999],
   [5447, 7035],
   [5647, 6967],
   [5435, 7645]])

Answer 6

`

>>> a = [[4251, 4254], [4123, 4290], [4323, 4222], [4111, 4900]] #original array
>>> b = [1324, 2745] #original array (note length of b and of individual lists of a must be same)
>>> c=[] #temporary list
>>> final_list=[]
>>> for val_a in a: #for each element(list) in a, compute c
    c=[]    #initialize temp list every time
    for index in range(len(b)): #for each element in b, compute c (note length issue mentioned above)
        c.append(val_a[index]+b[index]) #add the values and append to c
    final_list.append(c) #append c to final list


>>> final_list
[[5575, 6999], [5447, 7035], [5647, 6967], [5435, 7645]]

`

很高兴帮助

将值添加到列表中的值范围？

6 个答案: