Question

我可以获得一个JSON对象数组

[
{
Id: "1",
StartNo: "1",
ChipNo: "0",
CategoryId: "0",
Wave: "0",
Club: "",
FirstName: "Lotta",
LastName: "Svenström",
FullName: "Lotta Svenström",
ZipCode: "24231"
},
{...}
]

我想创建一个仅包含StartNo和FullName的新数据结构。我如何实现这一目标？

我试过了：

$scope.runners = [];

for(var i = 0; i<data.length; i++){
    $scope.runners[i].StartNo = data[i].StartNo;
    $scope.runners[i].Fullname = data[i].Fullname;
}

但这不起作用。

Answer 1

您只能使用以下两个属性创建新对象：

for (var i = 0; i < $scope.runners.length; i++){
    $scope.runners[i] = {
        StartNo: data[i].StartNo,
        Fullname: data[i].Fullname
    }
}

或者，如果您需要保留引用，请从对象中删除所有其他属性：

for (var i = 0; i < $scope.runners.length; i++){
    for (var k in $scope.runners[i]) {
        if ($scope.runners[i].hasOwnProperty(k) && k !== 'StartNo' && k !== 'Fullname') {
            delete($scope.runners[i][k]);
        }
    }
}

Answer 2

使用map - Array的功能：

var data = [...your JSON objects...];

$scope.runners = data.map(function(runner) {
    return {
        StartNo: runner.StartNo,
        Fullname: runner.Fullname
    };
});

Answer 3

您可以使用本地map，如下文

var $scope.runners = data.map(function(obj){
                     return {StartNo:obj.StartNo,FullName:obj.FullName};
                     });

Answer 4

试试这段代码

    var data=[
{
Id: "1",
StartNo: "1",
ChipNo: "0",
CategoryId: "0",
Wave: "0",
Club: "",
FirstName: "Lotta",
LastName: "Svenström",
FullName: "Lotta Svenström",
ZipCode: "24231"
}
];

var runners =[];


for(var i = 0; i<data.length; i++){
runners[i]={};
   runners[i].StartNo = data[i].StartNo;
    runners[i].Fullname = data[i].Fullname;
}

Answer 5

 $scope.runners=[];
$scope.sampleRunner = [
    {
        Id: "1",
        StartNo: "1",
        ChipNo: "0",
        CategoryId: "0",
        Wave: "0",
        Club: "",
        FirstName: "Lotta",
        LastName: "Svenström",
        FullName: "Lotta Svenström",
        ZipCode: "24231"
    },
    {
        Id: "1",
        StartNo: "2",
        ChipNo: "0",
        CategoryId: "0",
        Wave: "0",
        Club: "",
        FirstName: "Lotta",
        LastName: "Svenström",
        FullName: "Velu",
        ZipCode: "24231"
    },];

    angular.forEach($scope.sampleRunner, function (data) {
            $scope.runners.push({ StartNo: data.StartNo, FullName: data.FullName });
        });

在JavaScript中只有特定的JSON属性

5 个答案: