我有NSDictionary与键及其值,我希望它填充到tableview但我得到这样的错误:
-[__NSArrayM isEqualToString:]: unrecognized selector sent to instance 0x8f8e4d0
2014-08-13 13:29:45.357 SotaApp[1602:60b] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[__NSArrayM isEqualToString:]: unrecognized selector sent to instance 0x8f8e4d0'
我试过的是:
NSString *value = [filteredDictionaryValues valueForKey:[filteredDictionaryValues.allKeys objectAtIndex:indexPath.row]];
cell.textLabel.text =[filteredDictionaryValues.allKeys objectAtIndex:indexPath.row];
cell.detailTextLabel.text = value;
请告诉我这是什么问题, 谢谢。
修改 字典看起来像这样:
activity = (
"0Pharmacology.html"
);
acute = (
"0Pharmacology.html"
);
adenosine = (
"0Guidelines Precautions.html"
);
administration = (
"0Guidelines Precautions.html"
);
aneurysm = (
"0Dilution for Infusion.html"
);
arrhythmias = (
"0Guidelines Precautions.html"
);
artery = (
"0Dilution for Infusion.html"
);
asthma = (
"0Guidelines Precautions.html"
);
atrium = (
"0Dosing.html"
);
我已经从搜索方法中过滤了字典:
-(void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText
{
if (searchText.length == 0) {
isSearching = NO;
}
else{
isSearching = YES;
}
NSPredicate *predicate =[NSPredicate predicateWithFormat:@"self beginswith[c] %@",searchText];
NSArray *filteredKeys =[[myDictionary allKeys]filteredArrayUsingPredicate:predicate];
NSLog(@"filtered keys are %@",filteredKeys);
filteredDictionaryValues =[myDictionary dictionaryWithValuesForKeys:filteredKeys];
NSLog(@"filteredDicValues are %@",filteredDictionaryValues);
[self.SerchTable reloadData];
}
答案 0 :(得分:0)
当您调用[filteredDictionaryValues valueForKey:[filteredDictionaryValues.allKeys objectAtIndex:indexPath.row]]
时,返回的值是带有1个字符串对象(NSArray *array = [filteredDictionaryValues valueForKey:[filteredDictionaryValues.allKeys objectAtIndex:indexPath.row]]; NSString *string = [array firstObject];
)的NSArray。如果可以的话,你应该改变填充字典的方式(而不是只有1个对象的数组对象)。如果没有,只需使用返回数组中的firstObject。