我一直试图让这项工作暂时搁置一段时间。我在一个应用程序上工作，用户使用用户名和密码登录，该用户名和密码使用httppost请求发布到服务器。我得到了正确的答案，在帖子中我存储了服务器给我的会话cookie。 （我把它存放在一个cookie商店） 但是当我在登录后尝试单击菜单上的链接（执行第二个http帖子）时，服务器会给我一条消息，说我没有登录。但是我发送了第一篇文章中收到的cookie到第二篇文章中的服务器，但服务器无法识别我已登录。为了更容易地测试这个我使用“邮差”中的chrome插件，它可以让你轻松地发布到网站。它唯一有效的时间是我使用chrome登录网站，然后使用Postman做第二篇文章，成功地给了我一个回复。但是，当我使用Postman登录时，还要使用邮递员再次尝试第二篇文章“未登录”。我猜测cookie没有正确存储在应用程序中。我怎么能解决这个问题呢？我读了一些关于将cookie存储在“共享首选项”中的东西，这可能是一个修复方法吗？如果是这样，它是什么以及如何将饼干存储在那里？
public static String executeHttpPost(String url, ArrayList<NameValuePair> postParameters) throws Exception {
BufferedReader in = null;
try {
LoginLayout.httpClient = new DefaultHttpClient();
HttpPost request = new HttpPost(url);
UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters);
request.setEntity(formEntity);
CookieStore cookiestore = LoginLayout.httpClient.getCookieStore();
HttpResponse response = LoginLayout.httpClient.execute(request);
List<Cookie> cookies = LoginLayout.httpClient.getCookieStore().getCookies();
cookiestore.addCookie(cookie);
cookie = cookies.get(0);
cookieValue = "ASPSESSIONIDCQTCRACT=" + cookiestore.getCookies();
System.out.println("The cookie" + cookieValue);
List<Cookie> cookiess = cookiestore.getCookies();
cookiee = cookies.get(0);
Header[] headers = response.getAllHeaders();
System.out.println("length" + headers.length);
for (int i=0; i < headers.length; i++) {
Header h = headers[i];
System.out.println( "Header names: "+h.getName());
System.out.println( "Header Value: "+h.getValue());
}
in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer sb = new StringBuffer("");
String line = "";
String NL = System.getProperty("line.separator");
while ((line = in.readLine()) != null) {
sb.append(line + NL);
}
in.close();
// System.out.println( mCookie);
String result = sb.toString();
return result;
}
finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
e.printStackTrace();
}
}
} }
这是getter，所以我可以在下一个活动中从cookie商店访问cookie
public static String getCookie(){
return cookiee.getName() +"="+cookiee.getValue();
}
这是第二篇文章，我试图检索存储的cookie，它似乎成功，但服务器无法识别我已登录
public static String executeHttpPost(String url, ArrayList<NameValuePair> postParameters) throws Exception {
BufferedReader in = null;
try {
HttpPost request = new HttpPost(url);
request.setHeader("Cookie", LoginLayout.getCookie());
UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters);
request.setEntity(formEntity);
HttpResponse response = LoginLayout.httpClient.execute(request);
Header[] headers = response.getAllHeaders();
System.out.println("length" + headers.length);
for (int i=0; i < headers.length; i++) {
Header h = headers[i];
System.out.println( "Header names: "+h.getName());
System.out.println( "Header Value: "+h.getValue());
}
in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer sb = new StringBuffer("");
String line = "";
String NL = System.getProperty("line.separator");
while ((line = in.readLine()) != null) {
sb.append(line + NL);
}
in.close();
//System.out.println( mCookie);
String result = sb.toString();
return result;
}
finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
答案 0 :(得分：0)
您必须确保您的HttpClient在每个请求上使用相同的HttpContext。 CookieStore与HttpContext相关联，因此创建一个新的HttpContext实例也将创建一个新的CookieStore。
我找到的最好的方法是创建一个HttpContext的静态实例，并在每个请求中使用它。 下面我添加了我在我的应用程序中使用的类的一部分：
public class ApiClient {
// Constants
private final static String TAG = "ApiClient";
private final static String API_URL = "your-url";
// Data
private static ApiClient mInstance;
private HttpClient mHttpClient;
private ThreadSafeClientConnManager mConnectionManager;
private HttpPost mPost;
/*
* we need it static because otherwise it will be recreated and the session
* will be lost
*/
private static HttpContext mHttpContext;
private HttpParams mParams;
private Context mContext;
public ApiClient(Context pContext) {
mParams = new BasicHttpParams();
mContext = pContext;
if (null == mHttpContext) {
CookieStore cookieStore = new BasicCookieStore();
mHttpContext = new BasicHttpContext();
mHttpContext.setAttribute(ClientContext.COOKIE_STORE, cookieStore);
}
ConnManagerParams.setMaxTotalConnections(mParams, 300);
HttpProtocolParams.setVersion(mParams, HttpVersion.HTTP_1_1);
SchemeRegistry schemeRegistry = new SchemeRegistry();
schemeRegistry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
mConnectionManager = new ThreadSafeClientConnManager(mParams, schemeRegistry);
mHttpClient = new DefaultHttpClient(mConnectionManager, mParams);
}
public static ApiClient getInstance(Context pContext) {
if (null == mInstance) {
return (mInstance = new ApiClient(pContext));
} else {
return mInstance;
}
}
public void testPOST() {
List<NameValuePair> requestParams = new ArrayList<NameValuePair>();
requestParams.add(new BasicNameValuePair("param1", "value1"));
requestParams.add(new BasicNameValuePair("param2", "value2"));
mPost = new HttpPost(API_URL);
try {
mPost.setEntity(new UrlEncodedFormEntity(requestParams, HTTP.UTF_8));
HttpResponse responsePOST = mHttpClient.execute(mPost, mHttpContext);
HttpEntity resEntity = responsePOST.getEntity();
String result = EntityUtils.toString(resEntity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}
要测试它，请尝试设置正确的API_URL和
ApiClient api = ApiClient.getInstance(somContext);
api.testPOST();