在Ruby中,如何从该类的实例中调用类方法?说我有
class Truck
def self.default_make
# Class method.
"mac"
end
def initialize
# Instance method.
Truck.default_make # gets the default via the class's method.
# But: I wish to avoid mentioning Truck. Seems I'm repeating myself.
end
end
行Truck.default_make
检索默认值。但有没有提到Truck
的方法呢?好像应该有。
答案 0 :(得分:520)
在实例方法中,您只需调用self.class.whatever
,而不是引用类的文字名称。
class Foo
def self.some_class_method
puts self
end
def some_instance_method
self.class.some_class_method
end
end
print "Class method: "
Foo.some_class_method
print "Instance method: "
Foo.new.some_instance_method
输出:
Class method: Foo Instance method: Foo
答案 1 :(得分:170)
使用self.class.blah
与继承时使用ClassName.blah
不同。
class Truck
def self.default_make
"mac"
end
def make1
self.class.default_make
end
def make2
Truck.default_make
end
end
class BigTruck < Truck
def self.default_make
"bigmac"
end
end
ruby-1.9.3-p0 :021 > b=BigTruck.new
=> #<BigTruck:0x0000000307f348>
ruby-1.9.3-p0 :022 > b.make1
=> "bigmac"
ruby-1.9.3-p0 :023 > b.make2
=> "mac"
答案 2 :(得分:9)
要访问实例方法中的类方法,请执行以下操作:
self.class.default_make
以下是您的问题的替代解决方案:
class Truck
attr_accessor :make, :year
def self.default_make
"Toyota"
end
def make
@make || self.class.default_make
end
def initialize(make=nil, year=nil)
self.year, self.make = year, make
end
end
现在让我们使用我们的课程:
t = Truck.new("Honda", 2000)
t.make
# => "Honda"
t.year
# => "2000"
t = Truck.new
t.make
# => "Toyota"
t.year
# => nil
答案 3 :(得分:6)
self.class.default_make
答案 4 :(得分:5)
你正在以正确的方式做到这一点。类方法(类似于C ++或Java中的'静态'方法)不是实例的一部分,因此必须直接引用它们。
就此而言,在您的示例中,您可以更好地使'default_make'成为常规方法:
#!/usr/bin/ruby
class Truck
def default_make
# Class method.
"mac"
end
def initialize
# Instance method.
puts default_make # gets the default via the class's method.
end
end
myTruck = Truck.new()
类方法对于使用该类的实用程序类型函数更有用。例如:
#!/usr/bin/ruby
class Truck
attr_accessor :make
def default_make
# Class method.
"mac"
end
def self.buildTrucks(make, count)
truckArray = []
(1..count).each do
truckArray << Truck.new(make)
end
return truckArray
end
def initialize(make = nil)
if( make == nil )
@make = default_make()
else
@make = make
end
end
end
myTrucks = Truck.buildTrucks("Yotota", 4)
myTrucks.each do |truck|
puts truck.make
end
答案 5 :(得分:5)
如果您有权访问委托方法,则可以执行以下操作:
[20] pry(main)> class Foo
[20] pry(main)* def self.bar
[20] pry(main)* "foo bar"
[20] pry(main)* end
[20] pry(main)* delegate :bar, to: 'self.class'
[20] pry(main)* end
=> [:bar]
[21] pry(main)> Foo.new.bar
=> "foo bar"
[22] pry(main)> Foo.bar
=> "foo bar"
或者,如果你想要委托给一个或多个方法,你可能会更加清晰。实例:
[1] pry(main)> class Foo
[1] pry(main)* module AvailableToClassAndInstance
[1] pry(main)* def bar
[1] pry(main)* "foo bar"
[1] pry(main)* end
[1] pry(main)* end
[1] pry(main)* include AvailableToClassAndInstance
[1] pry(main)* extend AvailableToClassAndInstance
[1] pry(main)* end
=> Foo
[2] pry(main)> Foo.new.bar
=> "foo bar"
[3] pry(main)> Foo.bar
=> "foo bar"
提醒:
不要随意delegate
所有不会将状态更改为类和实例的内容,因为您将开始遇到奇怪的名称冲突问题。谨慎地做到这一点,只有在你检查后没有别的东西被压扁。
答案 6 :(得分:2)
还有一个:
class Truck
def self.default_make
"mac"
end
attr_reader :make
private define_method :default_make, &method(:default_make)
def initialize(make = default_make)
@make = make
end
end
puts Truck.new.make # => mac
答案 7 :(得分:1)
以下是针对此情况实施_class
方法的方法,该方法适用于self.class
。注意:不要在生产代码中使用它,这是为了感兴趣:)
来自:Can you eval code in the context of a caller in Ruby?以及http://rubychallenger.blogspot.com.au/2011/07/caller-binding.html
# Rabid monkey-patch for Object
require 'continuation' if RUBY_VERSION >= '1.9.0'
class Object
def __; eval 'self.class', caller_binding; end
alias :_class :__
def caller_binding
cc = nil; count = 0
set_trace_func lambda { |event, file, lineno, id, binding, klass|
if count == 2
set_trace_func nil
cc.call binding
elsif event == "return"
count += 1
end
}
return callcc { |cont| cc = cont }
end
end
# Now we have awesome
def Tiger
def roar
# self.class.roar
__.roar
# or, even
_class.roar
end
def self.roar
# TODO: tigerness
end
end
也许正确的答案是为Ruby提交补丁:)
答案 8 :(得分:-6)
与您的问题类似,您可以使用:
class Truck
def default_make
# Do something
end
def initialize
super
self.default_make
end
end