我这里有一个Php Ajax Live搜索。我需要做的是添加另一个元素或下拉列表进行搜索。如何在脚本中添加下拉值?
<input type="text" name="value1" id="value1">
<select id="value2" name="value2">
<option value="" selected="selected" disabled>Select an option...</option>
<option value=""></option>
<option value=""></option>
</select>
<div id="result" class="box1"></div>
<script type="text/javascript">
jQuery_1_9_1(document).ready(function () {
function load(query) {
jQuery_1_9_1.post('search.php', {
value1: query
}, function (search_bid) {
jQuery_1_9_1('#result').stop(true, true).fadeIn(200).html(search_bid);
}); //End ajax call
}
load(jQuery_1_9_1("#value1").val());
//Live search
jQuery_1_9_1("#value1").on('keyup', function () {
//Input field value
load(jQuery_1_9_1(this).val());
}); //End on function
}); //End document.ready state
</script>
的search.php
if(isset($_POST['value1'])) {
$search = $mysqli->real_escape_string($_POST['value1']);
$search = preg_replace("/[^A-Za-z0-9 ]/", '', $search);
$search = $_POST['value1'];
}
答案 0 :(得分:0)
您只需编辑JS以传递下拉列表值(您会注意到我也做了一些更改以避免重复代码):
<script type="text/javascript">
function load() {
jQuery_1_9_1.post('search.php', {
value1: jQuery_1_9_1('#value1').val(),
value2: jQuery_1_9_1('#value2').val()
}, function (search_bid) {
jQuery_1_9_1('#result').stop(true, true).fadeIn(200).html(search_bid);
}); //End ajax call
}
jQuery_1_9_1(document).ready(function () {
// Call load function whenever input or select changes
jQuery_1_9_1("#value1, #value2").on('change', load);
load();
}); //End document.ready state
</script>
现在您可以访问search.php
中的两个值$value1 = $_POST['value1'];
$value2 = $_POST['value2'];