Question

我有以下代码，它基本上连接了两个大表，另一个小的＆＃39; chromoName＆＃39;表然后用于排序一切的目的。我还从其中一列中提取一些数据并将其拆分为3列以允许排序过程。在一天结束时，我的表会生成一些我想删除的过多列。另外，我想将输出保存为我的数据库中的新TABLE（使用＆＃34;到MYNEWTABLE＆＃34;命令）。我想在所有服务专栏＆＃39;之后保存我的桌子的最终版本。已被删除。

select*
--into patient_agk_p
from chromosomes  --join the 'chrom' tbl to the BIG tbl for sorting purposes! 
inner join
(
select split_part(s2, '-', 1)s3,*
from
(select split_part(id2, ':', 1)s1,split_part(id2, ':', 2) s2, * 
from 

---creating consolidate table!
(
select COALESCE(a.promoterid_agk_p_k4,b.promoterid_agk_p_k27ac)id2, *
from agk_p_K4 a full join agk_p_k27ac b
on a.promoterid_agk_p_k4=b.promoterid_agk_p_k27ac
order by id2
)t1
---finished creating consolidate table

)t2
) t3 on s1=chromosomes.chromname  --done join the 'chrom' tbl to the BIG tbl for sorting purposes! 
order by chronumber,cast(s3 as int) --sort it!

所以在这里的某个地方也许 - 可以删除说，3或4列，然后将所有内容保存到patient_agk_p ???

Answer 1

使用*这里包括所有列，只列出你想要的列

select column1, column2, column3 -- replace with actual columns
--into patient_agk_p
from chromosomes  --join the 'chrom' tbl to the BIG tbl for sorting purposes! 
inner join
(
select split_part(s2, '-', 1)s3 -- ,* remove this if you have all the columns you need, or specify the ones you want.
from
(select split_part(id2, ':', 1)s1,split_part(id2, ':', 2) s2 -- ,* remove this if you have all the columns you need, or specify the ones you want.
from 

---creating consolidate table!
(
select COALESCE(a.promoterid_agk_p_k4,b.promoterid_agk_p_k27ac)id2 -- ,* remove this if you have all the columns you need, or specify the ones you want.
from agk_p_K4 a full join agk_p_k27ac b
on a.promoterid_agk_p_k4=b.promoterid_agk_p_k27ac
order by id2
)t1
---finished creating consolidate table

)t2
) t3 on s1=chromosomes.chromname  --done join the 'chrom' tbl to the BIG tbl for sorting purposes! 
order by chronumber,cast(s3 as int) --sort it!

包含＆＃39; *＆＃39;在每个查询的末尾，您将返回所有正在连接的表中的每一列。这是非常糟糕的做法（特别是与SELECT INTO结合使用），因为如果将来修改任何表，查询结果将会改变，并且很难知道原因，因为这些字段没有明确列出。

从非现有表中删除列（在SELECT完成之前......！）

1 个答案: