Question

我正在尝试完成我的猜谜游戏，但当用户输入正确的数字时，程序会崩溃我打算使用strcmpi函数来评估用户的选择，但似乎无效。我正在做的方法是使用c=getchar()直接与'y'或'n'进行比较。不知怎的，我对此感觉不好。
因此，如果这不是正确的方法，请告诉我什么是正确的方法我也收到警告说

隐含的函数声明＆＃str; strcmpi

我建造它。然后我尝试添加#include <string.h>，然后弹出更多错误，表明我是例如

警告：传递＆＃39; strcmpi＆＃39;的参数1在没有强制转换的情况下从整数生成指针[默认启用] |
注意：预期＆＃39; const char *＆＃39;但参数的类型为＆＃39; char＆＃39;

任何帮助都将不胜感激，这是我的程序代码：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#define MAX_NUMBER 100

int main(void) {
int randNum;
srand((int)time(0));
randNum = rand() % 100 + 1;

long guessNum;
int count = 0;

do {
    printf("\nplz enter a guess from integer 1 to 100: %d", randNum);
    scanf("%ld", &guessNum);

    if(scanf("%ld", &guessNum)==1)
        {

    if (guessNum < randNum && guessNum >= 1) {
        printf("your guess is lower than the selected number");
        count++;
        printf("\nyou have %d times left to try", 100 - count);
    }
    if (guessNum > randNum && guessNum <= 100) {
        printf("your guess is higher than the selected number");
        count++;
        printf("\nyou have %d times left to try", 100 - count);
    }
    if (guessNum < 1 || guessNum > 100) {
        printf("your guess is out of the range, plz pick between 1-100");
        count++;
        printf("\nyou have %d times left to try", 100 - count);
    }
    if (guessNum == randNum) {
            count++;
        printf("congrats you got the right answer, you used %d times to make the right     guess", count
               );

        printf("\nwould you like to have another round? (y/n)\n");

        char c;
        c = getchar();


        if(strcmpi(c, 'y') == 0)
            {
                count = 0;
            printf("plz enter an integer from 1 - 100: ");
            scanf("%ld", &guessNum);
            }
            else if(strcmpi(c, 'n') == 0)
                {
                    printf("the game is ended!");
            break;
                    }else
                    {
                     printf("plz enter either y or n!");
                        }

            }

            }
            else
            {
            printf("plz enter a valid integer from 1 - 100: \n");
            char c;
            while((c = getchar())!= '\n');
            count++;
            printf("\nyou have %d times left to try", 100 - count);
            }
            } while (count < MAX_NUMBER);
            printf("\nthe guess time is used out!");

            return 0;
            }

Answer 1

strcmpi()对字符串进行操作，但getchar()只检索单个字符。

你要么做这样的事情：

// make a string for comparison
char s[2]={0};
s[0]=getchar();
if (strcmpi(s, "y")==0)
{
 //etc
}

或者这个：

// compare single character
char c=0;
c=getchar();
if (c=='y')
{
 // etc
}

用户输入字符评估到常量字符

1 个答案: