Question

假设我有以下两个表格。我想要实现的是在A1.pagetitle，A1.content或A2.value中找到匹配后按顺序返回排名结果的搜索。

但我只需要在tmplvarid匹配特定值（在本例中为15或17）的第二个表中包含结果。

 mod_site_content (A1)
 +----+-----------+--------------+
 | id | pagetitle | content      |
 +----+-----------+--------------+
 | 1  | home      | <p> ... </p> |
 | 2  | project 1 | <p> ... </p> |
 | 3  | comment 1 | <p> ... </p> |
 | 4  | project 2 | <p> ... </p> |
 | 5  | project 3 | <p> ... </p> |
 | 6  | comment 2 | <p> ... </p> |
 | etc ...                       |
 +----+-----------+--------------+

 mod_site_tmplvar_contentvalues (A2)
 +----+-----------+-----------+-----------------+
 | id | tmplvarid | contentid | value           |
 +----+-----------+-----------+-----------------+
 | 1  | 2         | 1         | [{"key":"val"}] |
 | 2  | 2         | 2         | [{"key":"val"}] |
 | 3  | 5         | 1         | [{"key":"val"}] |
 | 4  | 5         | 5         | [{"key":"val"}] |
 | 5  | 15        | 4         | [{"key":"val"}] |
 | 6  | 15        | 5         | [{"key":"val"}] |
 | etc ...                                      |
 +----+-----------+-----------+-----------------+

我想我差不多了 - 目前我有：

SELECT DISTINCT A1.pagetitle, A1.content, A1.uri, A2.value,
    CASE
        WHEN A1.pagetitle LIKE ? THEN 1
        WHEN A1.content LIKE ? THEN 2
        WHEN A2.value LIKE ? THEN 3
    END AS rank
FROM mod_site_content A1
INNER JOIN mod_site_tmplvar_contentvalues A2
    ON A1.id = A2.contentid
WHERE pagetitle LIKE ?
    OR content LIKE ?
    OR value LIKE ?
ORDER BY rank

但这包括所有对应的contentid - 我不能在我的生活中弄清楚如何合并一个只包含某些条件的条件。

Answer 1

当你加入过滤连接列上的结果时，如此

在两个表格中回归：

SELECT DISTINCT A1.pagetitle, A1.content, A1.uri, A2.value,
    CASE
        WHEN A1.pagetitle LIKE ? THEN 1
        WHEN A1.content LIKE ? THEN 2
        WHEN A2.value LIKE ? THEN 3
    END AS rank
FROM mod_site_content A1
INNER JOIN mod_site_tmplvar_contentvalues A2
    ON A1.id = A2.contentid
    AND A2.tmplvarid IN(15,17)
WHERE (pagetitle LIKE ?
    OR content LIKE ?
    OR value LIKE ?)

DEMO

从mod_site_content返回行并从mod_site_tmplvar_contentvalues返回任何匹配

SELECT DISTINCT A1.pagetitle, A1.content, A1.uri, A2.value,
    CASE
        WHEN A1.pagetitle LIKE ? THEN 1
        WHEN A1.content LIKE ? THEN 2
        WHEN A2.value LIKE ? THEN 3
    END AS rank
FROM mod_site_content A1
LEFT JOIN mod_site_tmplvar_contentvalues A2
    ON A1.id = A2.contentid
    AND A2.tmplvarid IN(15,17)
WHERE (pagetitle LIKE ?
    OR content LIKE ?
    OR value LIKE ?)

DEMO

Answer 2

最后添加条件！

SELECT DISTINCT A1.pagetitle, A1.content, A1.uri, A2.value,
    CASE
        WHEN A1.pagetitle LIKE ? THEN 1
        WHEN A1.content LIKE ? THEN 2
        WHEN A2.value LIKE ? THEN 3
    END AS rank
FROM mod_site_content A1
INNER JOIN mod_site_tmplvar_contentvalues A2
    ON A1.id = A2.contentid
WHERE (pagetitle LIKE ?
    OR content LIKE ?
    OR value LIKE ?)
    AND A2.contentid in (15,17)

ORDER BY rank

执行内部联接筛选定义的值

2 个答案: