Question

我正在尝试使用JSONModel创建模型类。使用NSJSONSerialization后我的json Dictionary如下所示。

      {
apiStatus =     {
    message = SUCCESS;
    success = 1;
};
boardingPoints = "<null>";
inventoryType = 0;
seats =     (
            {
        ac = 0;
        available = 1;
        bookedBy = "<null>";
        commission = "<null>";
        fare = 1200;


    },
            {
        ac = 0;
        available = 1;
        bookedBy = "<null>";
        commission = "<null>";
        fare = 1200;


    },

  );
}

JSON看起来像这样：

   {"boardingPoints":null,"inventoryType":0,"apiStatus":{"success":true,"message":"‌SUCCESS"},"seats":[{"fare":1200,"commission":null,"bookedBy":null,"ac":false,"ava‌ilable":true},{"fare":1200,"commission":null,"bookedBy":null,"ac":false,"availabl‌e":true},]}

我有一个这样的模型类： -

 @interface Seat : JSONModel

 @property (nonatomic,strong)NSString *ac;
 @property (nonatomic,strong)NSString *available;
 @property(nonatomic,strong)NSString *bookedBy;
 @property(nonatomic,strong)NSString *comission;
 @property(nonatomic)NSNumber * fare;

对于映射键，我这样做了： -

 +(JSONKeyMapper*)keyMapper {
return [[JSONKeyMapper alloc] initWithDictionary:@{@"ac":@"ac",
                                                   @"available":@"available",
                                                   @"bookedBy":@"bookedBy",
                                                   @"commission":@"commission",
                                                   @"fare":@"fare", }];

}

但是当我尝试使用此模型时，我收到以下错误：

[JSONModel.m:252] Incoming data was invalid [Seat initWithDictionary:]. Keys missing: {(
bookedBy,
comission,
available,
ac,
fare,

)}

Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[__NSPlaceholderArray initWithObjects:count:]: attempt to insert nil object from objects[0]'

我正在使用它：

 //Using JSON Model.
    NSError *jsonError;
    seat = [[Seat alloc]initWithDictionary:jsonDictionary error:&jsonError];
    jsonArray = @[seat.ac,seat.available,seat.bookedBy,seat.comission,seat.fare];
    NSLog(@"JSON Model Array : %@", jsonArray);

如何正确使用？

Answer 1

首先，如果您的属性名称与字段名称匹配，则不需要覆盖+(JSONKeyMapper*)keyMapper。尝试为可以为null的字段添加可选关键字。

@interface Seat : JSONModel

@protocol Seat;

@property (nonatomic,strong)NSString *ac;
@property (nonatomic,strong)NSString<Optional> *available;
@property(nonatomic,strong)NSString<Optional> *bookedBy;
@property(nonatomic,strong)NSString *comission;
@property(nonatomic)NSNumber * fare;

@end

更进一步，您可以像这样在顶级课程中进行级联：

//Result.h
#import "Seat.h"
#import "APIStatus.h"
@interface Result: JSONModel

@property(nonatomic,strong) APIStatus *apiStatus;
@property(nonatomic,strong) NSString<Optional> *boardingPoints;
@property(nonatomic,strong) NSArray<Seat> *seats;
@property(nonatomic,strong) NSNumber *boardingPoints;

@end

//APIStatus.h
@interface APIStatus: JSONModel

@property(nonatomic,strong) NSString *message;
@property(nonatomic,strong) NSNumber *success;

@end

编辑：这样您只需要使用JSONModel初始化Result模型，所有中间类都将自动创建。您可能需要使用房产类型。如果您需要参考，JSONModel的github页面提供了大量的解释。

Answer 2

您需要更正您的JSON字符串 - 在最后一次输入座位后删除逗号。
我想你可能必须在这里表明你正在使用嵌套模型，即座位是顶层模型的嵌套模型，此时这些模型是匿名的，但实际上用顶级{}括号表示。

看看这个 - 它描述了如何使用嵌套模型进行设置。

JSONModel tutorial covering nested models

以下是您更正的JSON字符串：

{
"boardingPoints": null,
"inventoryType": 0,
"apiStatus": {
    "success": true,
    "message": "‌SUCCESS"
},
"seats": [
    {
        "fare": 1200,
        "commission": null,
        "bookedBy": null,
        "ac": false,
        "ava‌ilable": true
    },
    {
        "fare": 1200,
        "commission": null,
        "bookedBy": null,
        "ac": false,
        "availabl‌e": true
    }
]}

如何使用JSONModel创建模型类？

2 个答案: