Question

我是Python的新手，我的程序遇到了一些麻烦。每当我输入大于第一个数字的第二个数字时，“mCounter”应设置为false，并且由于有一个while循环，它应该让我再次输入数字位数。出于某种原因，这不会发生。每当我输入第二个数字大于第一个时，程序就会停止。任何帮助将不胜感激。谢谢！

import random 
#Introduction
print('Choose the mode that you would like to enter by typing the letters in the brackets')
problem = input('Multiplication(M) Addition (A) Subtraction (S) Division (D): ')
#Multiplication
if problem == 'M' or problem == 'm':
    mCounter = False
    while mCounter == False:
        mInput1 = int(input('Enter the amount of digits you would like in the first number you are multiplying.\nThe first number should be greater or equal to the second number: '))
        mInput2 = int(input('Enter the amount of digits you would like in the second factor: '))
        mCounter = True
        if mInput2 > mInput1:
            print('The first number MUST be greater or equal to the second number. Please try again!')
            mCounter == False
        else:
            print('nothing')

Answer 1

要设置mCounter的值，请执行以下操作：

mCounter = False

而不是：

mCounter == False

您所拥有的代码只是比较 mCounter与False的值，然后忽略该比较的结果。

Answer 2

而不是：

mCounter == False

你想要：

mCounter = False

您需要一项任务，而不是条件检查。

Answer 3

声明mCounter == False不会改变mCounter。您必须使用=进行分配。

if mInput2 > mInput1:
    print('The first number MUST be greater or equal to the second number. Please try again!')
    mCounter = False #<-- use = instead of ==

Python不会返回while循环

3 个答案: