Question

我使用Ajax请求检查会话是否有效。

我使用以下代码来完成它......

function checksession() {
        $.ajax({
            type:'POST'
            ,url:'CheckSession'
            ,success: validateresult
            ,data: { antiCSRF : '{{acsrf}}',
                   session_id: '{{session_id}}'}
            ,error: function(){ alert('Session check failed') }
            })

function validateresult(session_ind){
            alert('called_form validateresult = ' + called_for)
            if (session_ind == "Y"){
                    alert_message = "Y"
                    if (called_for == "SEARCH") {formSubmit()}
                    else if (called_for == "ENTER" ) {formSubmit();}
                    else if (called_for == 'DATA') { $('#datasetform').submit();}
                    else if (called_for == 'FEEDBACK') { createfeedback()}
                    else if (called_for == 'HELP') {createhelp()}
            }else{
                    if (alert_message == "Y") {
            alert("Your session has been timed-out ");
            }
               alert_message = "Y";
               window.location = './';

            }
        }

一切正常......唯一的问题是我提交了一份表格提交......

 <form id="bigsearchform_new" method="post" action="Paid">
                        <label style="display:none" for="search_string1">SEARCH</label>
                        <input id="search_string" name="search_string1" type="text" class="startnewsearch rounded" placeholder="Search..." maxlength="500" >
                        <input id="searchButton1"  type="button" class="searchButton" title="Click here to search the database">
                        <input type="hidden" name="antiCSRF" value="{{acsrf}}" />
                        <input type="hidden" name="session_id" value="{{session_id}}" />
                        <input type="hidden" name="commodity_id" id="commodity_id" />
                </form>

当我提交上述表格时，我会使用以下代码检查会话是否有效 -

 $('input[id=search_string]').on('keyup', function(e) {
    if (e.which == 13) {
        alert('called_for')
        called_for = "ENTER"
        checksession()
   }
   });

执行此操作时，将取消运行CheckSession的POST请求。

Chrome内部错误 -

t=254662 [st=60]        HTTP_TRANSACTION_READ_RESPONSE_HEADERS
                        --> HTTP/1.1 200 OK
                            Content-Type: text/html; charset=UTF-8
                            Date: Mon, 11 Aug 2014 19:31:36 GMT
                            Server: Apache
                            X-Frame-Options: DENY
                            Content-Length: 1
                            Connection: keep-alive

表格提交：

 function formSubmit()
    {
    alert('calling main page = ' + $("#search_string").val().length )
    if ($("#search_string").val().length != 0) {
        $("#bigsearchform_new").submit();
   } else {
        alert("Please enter a search term!");
   }

   }

Answer 1

它被取消，因为提交表单时没有等待会话检查。如果要在提交表单之前测试表单，则应使用on submit事件并返回false。

但为什么在提交之前检查会话？搜索脚本应该测试会话本身。

您设置了一个名为_from的全局变量。这不是好习惯。而是将会话检查功能作为参数提供回调函数。

function checksession(callback) {
    ...
            if (session_ind == "Y"){
                alert_message = "Y"
                callback()
   ...
}

然后这样称呼：

if (e.which == 13) {
    alert('called_for')
    called_for = "ENTER"
    checksession(formSubmit1())
}

使用Ajax请求检查会话

1 个答案: