Question

当我尝试跑步时，我输入每日罚款，我收到此错误“java.lang.stringindexoutofboundsexception string index out of range: 10 (in java.lang.String)"我不知道为什么。

import java.util.Scanner;
    public class Fines 
        {
            public static void main(String[] args) 
                {
                    //Makes the Scanner Object
                    Scanner in = new Scanner(System.in);
                    //Decoration
                    String decor = "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~";
                    //Integers
                    int chkMonthInt;
                    int chkDayInt;
                    int chkYearInt;
                    int lateMonthInt;
                    int lateDayInt;
                    int lateYearInt;
                    int monthsLate;
                    int daysLate;
                    int yearsLate;
                    double rateDouble;
                    //Obtaining Information
                    System.out.print("Enter Last Name: ");
                    String Last = in.next();
                    System.out.print("Enter First Name: ");
                    String First = in.next();
                    System.out.print("Enter SSN: ");
                    String SSN = in.next();
                    System.out.print("Enter the title of the book: ");
                    String TitleA1 = in.next();
                    String TitleA2 = in.nextLine();
                    System.out.print("Enter the date checked out (MM/DD/YYYY): ");
                    String Date = in.next();
                    System.out.print("Enter current date (MM/DD/YYYY): ");
                    String Due = in.next();
                    System.out.print("Enter daily fine rate: ");
                    String Rate = in.next();
                    //Stringing Checkout dates
                    String chkMonth = Date.substring(0, 2);
                    String chkDay = Date.substring(3, 5);
                    String chkYear = Date.substring(6, 10);
                    //Stringing Due dates
                    String lateMonth = Due.substring(0, 2);
                    String lateDay = Due.substring(3, 5);
                    String lateYear = Due.substring(6, 10);
                    //Parsing
                    chkMonthInt = Integer.parseInt(chkMonth);
                    chkDayInt = Integer.parseInt(chkDay);
                    chkYearInt = Integer.parseInt(chkYear);
                    lateMonthInt= Integer.parseInt(lateMonth);
                    lateDayInt = Integer.parseInt(lateDay);
                    lateYearInt = Integer.parseInt(lateYear);
                    rateDouble = Double.parseDouble(Rate);
                    //Calculations
                    monthsLate = (lateMonthInt - chkMonthInt);
                    daysLate = (lateDayInt - chkDayInt);
                    yearsLate = (lateYearInt - chkYearInt);
                    //Print out the information
                    System.out.println("\n");
                    System.out.println("To: " + Last + ", " + First + "\t\tAccount: " + Last + First.substring(0, 3) + SSN.substring(6, 10));
                    System.out.println("From: Librarian");
                    System.out.println("Subject: Overdue Notice");
                    System.out.println(decor);
                    System.out.println(TitleA1 + TitleA2 + " was checked out on: " + Date);
                    System.out.println("This book is currently " + monthsLate + "/" + daysLate + "/" + yearsLate + " days late.");
                    System.out.println("Your fine has accumulated to: $" + (daysLate * rateDouble));


                }

        }

Answer 1

这意味着您正在尝试引用大于实际数组大小的数组索引。

Answer 2

Java是零索引的。假设您的社交是123456789，即0-8，所以呼叫6-10不会工作，如果你想要最后4，它将是5-9（因为最后是非包容性的）。此外，您需要解析此问题，如果用户输入123-45-6789，该怎么办？

但是，您实际上并没有显示您获得此项的哪一行，但上面的示例显示了您的所有 - 第十个子字符串方法中的错误。

解决上述问题的方法就像

一样简单

SSN.substring(SSN.length() - 4, SSN.length())

Answer 3

String Date或String Due中的一个（或两个）长度不是10个字符，

String chkMonth = Date.substring(0, 2);
String chkDay = Date.substring(3, 5);
String chkYear = Date.substring(6, 10); // <-- Here
//Stringing Due dates
String lateMonth = Due.substring(0, 2);
String lateDay = Due.substring(3, 5);
String lateYear = Due.substring(6, 10); // <-- and/or Here

我能看到的最简单的解决方案是添加支票。

 String chkYear = (Date.length() >= 10) ? Date.substring(6, 10) : "";
 // ...
 String lateYear = (Due.length() >= 10) ? Due.substring(6, 10) : "";

此外，Java命名约定为String date和String due。您的Date和Due类似于类名。

Answer 4

您确定正确填写了日期和截止字符串吗？可能是你正在尝试从不长的字符串中获取子字符串。：）

可以在此处找到更多信息：http://docs.oracle.com/javase/7/docs/api/java/lang/StringIndexOutOfBoundsException.html

或在这里

Java substring : string index out of range

未知的Java错误

4 个答案: