Question

您好我正在使用表单向查询中插入新值。
我得到的错误是：数组到字符串转换。
我应该改变什么才能得到这个错误？

谢谢

if( isset($_POST["new_log"]) ){

//mysql_real_escape_string - ochrana proti mysql injection

$name       = $_POST["name"];
$surname    = $_POST["surname"];
$password   = $_POST["password"];
$email      = $_POST["email"];
$salary     = $_POST["salary"];
$msaving    = $_POST["msaving"];
$mfixpayment = $_POST["mfixpayment"];
$lastupdate = $_POST["lastupdate"];
$bio        = $_POST["bio"];
$money      = $_POST["money"];

$new_log=" INSERT INTO login SET `name`='$name', `surname`='$surname', `password`='$password', `email`='$email', `salary`='$salary', `msaving`='$msaving', `mfixpayment`='$mfixpayment', `lastupdate`='$lastupdate', `bio`='$bio', `money`='$money' ";

mysql_query( $new_log ) or die( mysql_error() );

}

这里我按表单

插入新值

    echo ' <form method="post"> ';  
    echo ' meno:                <input type="text" name="name['. $row_log["id"] .']" >  <br />';
    echo ' priezvisko:          <input type="text" name="surname['. $row_log["id"] .']">  <br />';
    echo ' heslo:               <input type="text" name="password['. $row_log["id"] .']">  <br />';
    echo ' e-mail:              <input type="text" name="email['. $row_log["id"] .']">  <br />';
    echo ' vyplata:             <input type="number" name="salary['. $row_log["id"] .']">  <br />';
    echo ' chcem mesačne ušetriť <input type="number" name="msaving['. $row_log["id"] .']">  <br />';
    echo ' platím každý mesiac: <input type="number" name="mfixpayment['. $row_log["id"] .']">  <br />';
    echo ' posledná mena:       <input type="date" name="lastupdate['. $row_log["id"] .']">  <br />';
    echo ' niečo o sebe:        <input type="text" name="bio['. $row_log["id"] .']">  <br />';
    echo ' mám na účte:         <input type="number" name="money['. $row_log["id"] .']">  <br />';
    echo "<br />";

    echo '<input type="submit" name="new_log" value="Pridať nového užívateľa" >';
    echo '</form>';

Answer 1

$name       = $_POST["name"];

应该是

$name       = $_POST["name"][$id];

或者，输出：

<input type="text" name="name" >

而不是

<input type="text" name="name['. $row_log["id"] .']" >

PHP - 使用表单进行数组到字符串转换

1 个答案: