Question

我尝试从我的数据库中检索Timestamp，我需要将其转换为java.util.Date

我一直在关注我在stackoverflow中找到的几个例子，但我一直遇到以下异常：

java.lang.IllegalArgumentException: Timestamp format must be yyyy-mm-dd hh:mm:ss[.fffffffff]

我不知道为什么，我已经尝试了几种方法，你能帮助我吗？

这是我的代码：

//select all partitions from table "LDRS"
stmtSelect = connection.prepareCall("Select HIGH_VALUE from user_tab_partitions where table_name = 'LDRS'");

ResultSet rs = stmtSelect.executeQuery();

SimpleDateFormat myFormat = new SimpleDateFormat("dd.MM.yyyy");

while (rs.next()) {
    try {
        Timestamp ts = rs.getTimestamp("HIGH_VALUE");
        Date date1 = myFormat.parse(ts.toString());
        Date date2 = myFormat.parse(""+new Date());
        // compares the current date with the partition date, if the difference between them is more than 30 days
        // drops the partition
        long diff = date2.getTime() - date1.getTime(); 
...
}

Answer 1

停止将值转换为字符串并返回。 java.sql.Timestamp已经一个java.util.Date：

long now = System.currentTimeMillis();

while (rs.next()) {
    Timestamp ts = rs.getTimestamp("HIGH_VALUE");
    long diff = ts.getTime() - now;
    ... use diff ...
}

当您从根本上想要这样做时，只应处理字符串。在这种情况下，＆＃34;找到存储的时间戳和当前时间之间的差异＆＃34;与字符串表示无关。

错误时间戳格式

1 个答案: