出于某种原因,当我填写表单并单击“提交”时,它不会将信息放入.txt文件中。
<table id="hor-zebra" summary="Employee Pay Sheet">
<thead>
<tr>
<th width="27%" scope="col">Name</th>
<th width="31%" scope="col">Email</th>
<th width="42%" scope="col">Comment</th>
</tr>
</thead>
<tbody>
<tr class="odd">
</tr>
<tr>
</tr>
<tr class="odd">
</tr>
<tr>
</tr>
<?php
$blogFile = 'blog.txt';
if (file_exists($blogFile))
{
$readfile = file($blogFile);
for ($k=0; $k<=count($readfile)-1; $k++) {
$fields = split("\t",$readfile[$k]);
print("<tr>");
print("<td>$fields[0]</td>");
print("<td>$fields[1]</td>");
print("<td>$fields[2]</td>");
print("</tr>");
}
}
?>
</tbody>
</table>
<h2>Blog</h2>
<form method="post" action="writeBlog.php">
<div class="row half">
<div class="6u">
<input type="text" class="text" name="Name" id="Name" placeholder="Name" />
</div>
<div class="6u">
<input type="text" class="text" name="Email" id="Email" placeholder="Email" />
</div>
</div>
<div class="row half">
<div class="12u">
<textarea name="Comment" placeholder="Comment" id="Comment"></textarea>
</div>
</div>
<div class="row">
<div class="12u"> <a href="writeBlog.php" class="button">Submit comment</a> </div>
</div>
</form>
这是处理from。的PHP代码。
<?php
$out = fopen("blog.txt", "a");
if (!$out) {
header('Location: blog.php');
exit;
}
$Name = $_POST['Name'];
$Email = $_POST['Email'];
$Comment = $_POST['Comment'];
$Comment = str_replace("\n", " ", $Comment);
fputs($out,"$Name\t");
fputs($out,"$Email\t");
fputs($out,"$Comment\n");
fclose ($out);
header('Location: blog.php');
exit;
?>
<!DOCTYPE html>
<html>
<head>
</head>
<body>
</body>
</html>
为什么此代码不会将信息放入.txt文件?
答案 0 :(得分:0)
这<a href="writeBlog.php" class="button">Submit comment</a>
并没有做到你期望它做的事情;使用实际的提交按钮,而不是文件的href
链接。
替换
<a href="writeBlog.php" class="button">Submit comment</a>
与
<input type = "submit" name = "submit" value = "Submit comment">
您的表单已采取行动。
<form method="post" action="writeBlog.php">