Question

这是下面的出勤记录表。

         Code    Name    Date        day1          Status
       -------  ------  ---------    --------    -------------------
         724    Ramesh  1-May-14    Thursday       Present 
         724    Ramesh  2-May-14    Friday         Present 
         724    Ramesh  3-May-14    Saturday       ½Present  On Leave(½CL)
         724    Ramesh  4-May-14    Sunday         WeeklyOff 
         724    Ramesh  5-May-14    Monday         ½Present  On Leave(½CL)
         724    Ramesh  6-May-14    Tuesday        ½Present  On Leave(½CL)
         724    Ramesh  7-May-14    Wednesday      Present 
         724    Ramesh  8-May-14    Thursday       ½Present 
         724    Ramesh  9-May-14    Friday         Present 
         724    Ramesh  10-May-14   Saturday       Present 
         724    Ramesh  11-May-14   Sunday         WeeklyOff  ½Present 
         724    Ramesh  12-May-14   Monday          Present 
         724    Ramesh  13-May-14   Tuesday         Present 
         724    Ramesh  14-May-14   Wednesday       Present 
         724    Ramesh  15-May-14   Thursday        Present 
         724    Ramesh  16-May-14   Friday          Present 
         724    Ramesh  17-May-14   Saturday        Present 
         724    Ramesh  18-May-14   Sunday         WeeklyOff 
         724    Ramesh  19-May-14   Monday           Present 
         724    Ramesh  20-May-14   Tuesday       Present  On Leave(½CL)
         724    Ramesh  21-May-14   Wednesday       ½Present 
         724    Ramesh  22-May-14   Thursday       Absent
         724    Ramesh  23-May-14   Friday           Present 
         724    Ramesh  24-May-14   Saturday         Present 
         724    Ramesh  25-May-14   Sunday           WeeklyOff 
         724    Ramesh  26-May-14   Monday            Present 
         724    Ramesh  27-May-14   Tuesday         Present 
         724    Ramesh  28-May-14   Wednesday       Present 
         724    Ramesh  29-May-14   Thursday       Present 
         724    Ramesh  30-May-14   Friday          Present 
         724    Ramesh  31-May-14   Saturday         Present

预期输出为：

       EmployeeCode      EmployeeName   Monday      Saturday      TotalLeaves
       -------------    --------------  -------     ----------    ------------
          724              Ramesh        0.5         0.5             4(days)

我试图根据状态栏

获取一个月内周一和周六的假期数

我的查询是

    select EmployeeCode
           ,EmployeeName
           ,AttendanceDate
           ,datename(dw,AttendanceDate) as 'day1'
           ,InTime
           ,a.PunchRecords
           ,a.Status 
    from   AttendanceLogs a 
    join   Employees b on a.EmployeeId=b.EmployeeId 

    where  AttendanceDate  >='2014-05-01'    
    and    AttendanceDate <='2014-05-31' 
    and    EmployeeCode='724'
    and    datename(dw,AttendanceDate) IN('Monday','Saturday') 
    and    a.Status!='present'

   order by AttendanceDate

请帮助我获得预期的输出。

Answer 1

我猜是这样的：

WITH cte AS (
SELECT  code ,
        name ,
        [date] ,
        CASE WHEN [status] LIKE '1/2Present%' THEN 0.5
             WHEN [status] = 'Absent' THEN 1
             ELSE 0
        END AS StatusAdder
FROM    tablename
WHERE   attendancedate >= '2014-05-01'
        AND attendancedate <= '2014-05-31'
        AND code = '724'
)

SELECT  code ,
        name ,
        CASE WHEN DATEPART(WEEKDAY, date) = 2 THEN SUM(statusAdder) END AS Monday ,
        CASE WHEN DATEPART(WEEKDAY, date) = 7 THEN SUM(statusAdder) END AS Saturday ,
        SUM(statusAdder) AS TotalLeaves
FROM    cte
GROUP BY code ,
        name

您必须使用对象名称进行调整。

CASE语句中的SUM和COUNT

1 个答案: