Question

我正在使用Xcode中的应用程序并遇到了问题。我的应用程序需要从TextField（用户输入信息的地方）收集输入，并将其放入我的等式＆amp;最终给用户一个结果。

例如 - a 用户输入他们的体重，身高和年龄。

我的应用程序需要接受这些输入并将它们放入以下等式中：

Men: RMR = 66,473 + (13,751*WEIGHT) + (5,0033*HEIGHT) - (6,755*AGE)

但我该怎么编码呢？到目前为止我所做的：

我的.h文件如下：

#import <UIKit/UIKit.h>

IBOutlet UITextField *Weight;
IBOutlet UITextField *Height;
IBOutlet UITextField *Age;

IBOutlet UILabel *rectResult;


@interface ViewController : UIViewController

@property (weak, nonatomic) IBOutlet UITextField *Weight;
@property (weak, nonatomic) IBOutlet UITextField *Height;
@property (weak, nonatomic) IBOutlet UITextField *Age;

@property (weak, nonatomic) IBOutlet UILabel *rectResult;

-(IBAction)calculate:(id)sender;


@end

和我的.m文件：

@implementation ViewController



-(IBAction)calculate:(id)sender {
    float floatRectResult=[Weight.text floatValue]*
    [Age.text floatValue];
    NSString *stringRectResult=[[NSString alloc]
                                initWithFormat:@"%1.2f",floatRectResult];

    rectResult.text=stringRectResult;


}





- (void)viewDidLoad
{
    [super viewDidLoad];

}

- (void)didReceiveMemoryWarning
{
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}

PS：对不起我的英语 - 有人可以帮帮我吗？：）

Answer 1

尝试这样的事情：

-(IBAction)calculate:(id)sender {

    //66,473 + (13,751*WEIGHT) + (5,0033*HEIGHT) - (6,755*AGE)
    float result = (66473 + (13751*[Weight.text floatValue]) + (50033*[Height.text floatValue]) - (6755*[Age.text floatValue]));

    rectResult.text = [NSString stringWithFormat:@"%.2f", result];
}

由于您似乎正在使用某些常量，因此#define可能更好，以便您以后可以轻松更改它们。例如：

//Above your implementation
#define kWeightConst 13751.0 //Can be used later as just kWeightConst

在textfield中计算带有输入的等式 - Xcode

1 个答案: