Question

我有一个使用SQLAlchemy填充对象的数据库，但我无法弄清楚如何在Django中创建模型。

我需要Show对象通过关系拥有Episode对象的数组。在数据库中，所有Episode对象都有一个＆＃39; show_title＆＃39;列和所有Show对象都有＆＃39;剧集＆＃39;

使用 SQLAlchemy ，

，对象看起来像这样

   class AlphaShow(Base) :    
    __tablename__ = 'show' 
    title = Column(UnicodeText, primary_key = True)
    description = Column(UnicodeText)
    image = Column(UnicodeText)
    episodes = relationship("Episode", backref="show")
    def __init__(self,_meta) :
        self.title = _meta.title
        self.image = _meta.image
        self.description = _meta.description

class Episode (Base) : #was without base 
    __tablename__= 'episode'
    title = Column(UnicodeText, primary_key = True)
    link = Column(UnicodeText)
    show_title = Column(UnicodeText, ForeignKey('show.title'))

    def __init__(self, _title, _link) :
        self.title = _title
        self.link = _link

我如何在 Django 中制作模型？我试过了，但它没有用，

class Shows(models.Model) :
    episodes = [] 
    title = models.TextField(primary_key=True)
    description = models.TextField()  
    image = models.TextField()
    class Meta:
        db_table = 'shows'
    def __str__(self):
        return self.title  


class Episode(models.Model) :

    title = models.TextField(primary_key=True)
    link = models.TextField()  
    show_title = models.ForeignKey(Shows)

    class Meta: 
        db_table = 'episodes'
    def __str__(self):
        return self.title

我想我错过的是什么是Django等同于SQLAlchemy＆＃39;

episodes = relationship("Episode", backref="show")

非常感谢任何帮助！

Answer 1

试试这个

class Shows(models.Model) :
    title = models.TextField(primary_key=True)
    description = models.TextField()  
    image = models.TextField()
    class Meta:
        db_table = 'shows'
    def __str__(self):
        return self.title  


class Episode(models.Model) :
    show = models.ForeignKey(Show, related_name="episodes")
    title = models.TextField(primary_key=True)
    link = models.TextField()  
    show_title = models.ForeignKey(Shows)

    class Meta: 
        db_table = 'episodes'
    def __str__(self):
        return self.title

Django模型，一对多关系与后退参考[如何]

1 个答案: