Question

我有一个网站，可以从数据库中获取随机电影，然后将其显示给您。我想选择它而不重复（在没有显示其他电影时几次显示一部电影）并以最快的方式完成。

这就是我所拥有的：

$db = new mysqli($DBhost, $DBuser, $DBpassword, $DBdatabase);
$offset_result = " SELECT FLOOR(RAND() * COUNT(*)) AS `offset` FROM database";
$result = $db->query($offset_result);
$offset_row = $result->fetch_object();
$offset = $offset_row->offset;

$db = new mysqli($DBhost, $DBuser, $DBpassword, $DBdatabase);
$query = "SELECT id, title, year, front_image, category, watched, description, imdb_code, bg_image, scene_warning FROM database LIMIT $offset,1";
$stmt = $db->query($query);
list($id, $mtitle, $myear, $front_image, $category, $watched, $description, $imdb_code, $bg_image, $warning)=$stmt->fetch_row();

这是选择但重复...不重复，我有这个，但它很慢。

$db = new mysqli($DBhost, $DBuser, $DBpassword, $DBdatabase);
$query = "SELECT id, title, year, front_image, category, watched, description, imdb_code, bg_image, scene_warning FROM a358_filmovi WHERE id NOT IN (".$movies_array.") ORDER BY rand() LIMIT 1";
$stmt = $db->query($query);
list($id, $mtitle, $myear, $front_image, $category, $watched, $description, $imdb_code, $bg_image, $warning)=$stmt->fetch_row();

$ movies_array是包含电影ID的内爆会话数组。

所以，问题是，如何使查询与第一个（最快的一个）相同，但是使用包含ID的数组，以便电影不会重复？

Answer 1

为什么不首先将所有id拉入会话数组，选择随机索引，查找，然后从会话数组中删除该索引？

MySQL - 选择随机行而不重复

1 个答案: