Question

我正在使用socket.io和express编写聊天应用程序4.每当有人从login.html（客户端）登录时。服务器应该记住他的名字，并在线与人聊天。但在我的情况下，它只记得以后登录的名字（假设我先从John登录，然后罗恩再次记住罗恩。）。请帮助我对node.js来说是全新的

var express = require('express')
, app = express()
, http = require('http')
, server = http.createServer(app)
, Twit = require('twit')
, io = require('socket.io').listen(server)
, os = require('os')
, open = require('open')
, bodyParser = require('body-parser')
, mysql = require("mysql");

server.listen(9383,'192.168.1.3');

app.use(bodyParser.urlencoded({ extended: false }));
var name;

app.get('/', function (req, res) {
  res.sendfile(__dirname + '/login.html');
});

app.post('/valid', function (req, res) {
  console.log("hello");
  console.log(req.body.pass);
  var username=req.body.email;
  var password=req.body.pass;

    var connection = mysql.createConnection({
      "hostname": "localhost",
      "user": "root",
      "password": "vk123",
      "database": "login"
    });

    connection.connect();

//Verifying whether person exist if exist it gets its name. 

    connection.query('SELECT * FROM id WHERE email=? AND password=?', [username,password], function(err, rows){

      if (err){
        throw err;
      }else{
        for (var i in rows) {
           console.log('name: ', rows[i].name);
           name=rows[i].name;
           res.redirect('http://192.168.1.3:9383/chat.html');

        }
      }

    });

     connection.end();
});

// It is obtaining message from client and sending back message and name.

io.sockets.on('connection', function(socket){
  socket.on('chat message', function(msg){
    var chatmsg=[];
    console.log(name);
    console.log(msg);
    chatmsg.push({chatname:name, msgtext:msg}); 
    console.log('message: ' +chatmsg[0].chatname);
    io.emit('chat message',chatmsg);
  });
});

Answer 1

您应该阅读Javascript变量范围（http://msdn.microsoft.com/en-us/library/ie/bzt2dkta(v=vs.94).aspx）。

您的“名称”变量被定义为全局变量，这就是它被覆盖的原因。

socket.io和快速会话

1 个答案: