我一直在尝试使用WireShark解码来自IP摄像头的以下视频流。我试图解码为RTP，但一直收到无效的数据包。实际上我现在甚至都不认为它是RTP。
这是通过UDP传输的所有内容我只提取了数据。长线由有问题的IP摄像机发送，短线从服务器返回。这是连续流中的8个数据包。我所知道的系统这个数据没有加密。
我可以看到我认为的是序列号B8，B9，Ba，BB等。就我而言。任何帮助确定协议将非常感谢。 R.N
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如果我假设RTP它似乎不适合。首先版本是0，什么是时间戳不会上升。 PT在两种动态类型之间交替。
RTP
Version 0, Padding 0, Extension 0, CSRC = 0
PT [SN ] [timestamp] [SSRC ]
00 78 5D B8 17 EA 92 70 20 2C 0E 08
00 77 5D B9 17 63 92 80 18 20 0B 08
00 77 5D BA 17 DB 92 80 20 24 06 89
00 78 5D BB 17 52 94 70 30 18 05 08
答案 0 :(得分：0)
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这些似乎是RTP标头的开头。你看到有一个增量序列0x6D 0x6E 0x6F 0x70。有一个问题，这是wireshark数据包捕获吗？