嗨,我有一个问题,我是Android开发新手...我想在按下提交按钮后显示结果,而不是使用吐司功能,但我不知道我是怎么做的,任何帮助,将不胜感激。
这是我的代码:
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_system);
RadioGroup gender = (RadioGroup) findViewById(R.id.answer1);
gender.setOnCheckedChangeListener(new OnCheckedChangeListener() {
public void onCheckedChanged(RadioGroup group, int checkedId) {
// TODO Auto-generated method stub
switch (checkedId) {
case R.id.answer1A:
ans1 = 1;
break;
case R.id.answer1B:
ans1 = 2;
break;
}
}
});
RadioGroup nutrition = (RadioGroup) findViewById(R.id.answer2);
nutrition.setOnCheckedChangeListener(new OnCheckedChangeListener() {
public void onCheckedChanged(RadioGroup group, int checkedId) {
// TODO Auto-generated method stub
switch (checkedId) {
case R.id.answer2A:
ans2 = 1;
break;
case R.id.answer2B:
ans2 = 2;
break;
}
}
});
btnSubmitQuiz = (Button) findViewById(R.id.submit);
btnSubmitQuiz.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
// 1
if (ans1 == 1 && ans2 == 1) {
Toast.makeText(SystemActivity .this, "Well done", 5).show();
}
else {
Toast.makeText(SystemActivity .this, "Fail", 5).show();
}
}
});
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.system, menu);
return true;
}
}
答案 0 :(得分:1)
创建方法
private void displayResult(String result) {
Intent i = new Intent(this, showResult.class);
i.putExtra("unique_constant", result);
startActivity(i);
}
代替吐司写,
displayResult("Well done");
创建一个名为showResult的新Activity,确保它已添加到AndroidManifest文件中。在布局中添加textView。
在oncreate方法中写,
String result = getIntent().getStringExtra("unique_constant");
TextView txtView = (TextView) findViewById(R.id.txtViewId);
txtView.setText(result);
答案 1 :(得分:0)
您可能想要使用意图。
查看类似问题Android: passing data back and forth using intent setResults