我有下表:
Table games +----+----------+------+---------------------+ | id | name | win | date | +----+----------+------+---------------------+ | 1 | Fulano | Y | 2014-01-01 00:00:00 | | 2 | Fulano | Y | 2014-01-01 00:00:00 | | 3 | Fulano | Y | 2014-01-02 00:00:00 | | 4 | Fulano | Y | 2014-01-03 00:00:00 | | 5 | Fulano | N | 2014-01-03 00:00:00 | | 6 | Beltrano | N | 2014-01-01 00:00:00 | | 7 | Beltrano | N | 2014-01-01 00:00:00 | | 8 | Beltrano | N | 2014-01-02 00:00:00 | | 9 | Beltrano | Y | 2014-01-03 00:00:00 | | 10 | Cicrano | Y | 2014-01-03 00:00:00 | | 11 | Cicrano | N | 2014-01-03 00:00:00 | +----+----------+------+---------------------+
我想做点什么:
SELECT name,count(win ='Y')AS wins,count(win ='N')AS loss FROM games GROUP BY name;
显然,由于“count”无法识别我发明的命令,我收到了不需要的回复:
+----------+----------+----------+ | name | wins | losses | +----------+----------+----------+ | Beltrano | 4 | 4 | | Cicrano | 2 | 2 | | Fulano | 5 | 5 | +----------+----------+----------+
有人可以帮忙得到正确答案吗?
答案 0 :(得分:4)
SELECT
name,
SUM( win = 'Y' ) AS wins,
SUM( win = 'N' ) AS losses
FROM games
GROUP BY name;