Question

我有两张销售和收据表

表结构和结果表结构如下。

销售

date        |   total
------------+-----------
2014-08-09  |  500
2014-07-08  |   50
2014-07-08  |  100

收据

date        |    net_amount   
----------- +-----------------
2014-08-08  |      50
2014-08-08  |      50

预期结果

month     total      net_amount
-------+----------+---------------
07     |   150    |
08     |   500    |    100

QUERY

select MONTH(date),total,net_amount from (
select MONTH(date) as month,
sum(total) as total 2 as sort_col from
sale union all select MONTH(date) as month, 
sum(net_amount) as net_amount, 
1 as sort_col from receipt) 
as a order by MONTH(date) desc, sort_col desc

Answer 1

SELECT    s.`month`, total, net_amount
FROM      (SELECT   MONTH(sale.`date`) AS `month`, 
                    SUM(total) AS total
           FROM     sale
           GROUP BY MONTH(sale.`date`)) s
LEFT JOIN (SELECT   MONTH(receipt.`date`) AS `month`, 
                    SUM(net_amount) AS net_amount
           FROM     receipt
           GROUP BY MONTH(receipt.`date`)) r ON s.`month` = s.`month`

Answer 2

试试这个

 select Month(date),sum(total),sum(net_amount)
 from (
 select date,sum(total) as total,0 as net_amount from sale group by month(date)
 union all 
 select date, 0 as total,sum(net_amount) from receipt group by month(date)) 
 as tabl group by Month(date)

Sql Fiddle

选择查询无法使用mysql

2 个答案: