我正在尝试使用spring连接到服务以运行定义为
的soap操作https://services.domain.getuserbyid
这是我的代码,但它告诉我前缀" tem"不受约束。假设我的webServiceTemplate正在加载,任何想法我如何正确定义这个前缀所以我可以发送这个肥皂消息?如果需要更多信息,请告诉我。
import java.io.StringReader;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.ws.WebServiceMessage;
import org.springframework.ws.client.core.WebServiceMessageCallback;
import org.springframework.ws.client.core.WebServiceTemplate;
import org.springframework.ws.soap.SoapMessage;
import org.springframework.test.context.ContextConfiguration;
import org.springframework.test.context.TestExecutionListeners;
import org.springframework.test.context.junit4.SpringJUnit4ClassRunner;
import org.springframework.test.context.support.*;
@TestExecutionListeners( { DependencyInjectionTestExecutionListener.class })
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations={"spring-ws.xml"})
public class TestWebServiceClient {
private static final String ENVELOPE_PREFIX = "soap";
private static final String MESSAGE =
"<tem:GetUserByID> " +
"<tem:samAccountName>name</tem:samAccountName> " +
"</tem:GetUserByID> " ;
@Autowired
private WebServiceTemplate webServiceTemplate;
@Test
// send to the configured default URI
public void simpleSendAndReceive() {
StreamSource source = new StreamSource(new StringReader(MESSAGE));
StreamResult result = new StreamResult(System.out);
//webServiceTemplate.sendSourceAndReceiveToResult(source, result);
webServiceTemplate.marshalSendAndReceive(webServiceTemplate.sendSourceAndReceiveToResult(source, result), new WebServiceMessageCallback() {
public void doWithMessage(WebServiceMessage message) {
((SoapMessage)message).setSoapAction("https://services.domain.getuserbyid");
}});
}
public void setWebServiceTemplate(WebServiceTemplate webServiceTemplate) {
this.webServiceTemplate = webServiceTemplate;
}
public WebServiceTemplate getWebServiceTemplate() {
return this.webServiceTemplate;
}
}
我的春季应用上下文文件:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:oxm="http://www.springframework.org/schema/oxm"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:dwr="http://www.directwebremoting.org/schema/spring-dwr"
xmlns:mongo="http://www.springframework.org/schema/data/mongo"
xmlns:util="http://www.springframework.org/schema/util"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.2.xsd
http://www.springframework.org/schema/data/mongo
http://www.springframework.org/schema/data/mongo/spring-mongo-1.0.xsd
http://www.directwebremoting.org/schema/spring-dwr
http://www.directwebremoting.org/schema/spring-dwr-3.0.xsd
http://www.springframework.org/schema/util
http://www.springframework.org/schema/util/spring-util.xsd
http://www.springframework.org/schema/oxm
http://www.springframework.org/schema/oxm/spring-oxm.xsd">
<context:component-scan base-package="com.domain"/>
<context:annotation-config />
<bean id="soapMessageFactory" class="org.springframework.ws.soap.saaj.SaajSoapMessageFactory">
<property name="soapVersion">
<util:constant static-field="org.springframework.ws.soap.SoapVersion.SOAP_12"/>
</property>
</bean>
<bean id="webServiceTemplate" class="org.springframework.ws.client.core.WebServiceTemplate">
<constructor-arg ref="soapMessageFactory"/>
<property name="defaultUri" value="https://domain.com/Service.svc?WSDL"/>
</bean>
</beans>
答案 0 :(得分:2)
想出来,需要将它添加到我的XML
<tem:GetUserByID xmlns:tem="http://domain/GetUserByIDResponse/">
<tem:samAccountName>name</tem:samAccountName>
</tem:GetUserByID>