Question

我在存储过程中有以下SQL查询并尝试调用表值函数（fn_get_type_ids）。我得到＆＃39;必须声明标量变量＆＃34; @ category_id＆＃34;。＆＃39;错误信息。表值函数返回多个ID。我该如何调用此功能？如果我将硬编码值传递给函数，则存储过程有效。 dbo.fn_get_type_ids（2,90，NULL）。如果我传递下面显示的变量，它不起作用。可能有什么不对？请建议。

ALTER PROCEDURE [dbo].[get_search_results]
 @user_id                   BIGINT,
 @category_id           INT = NULL,
 @a_id                  INT = NULL,
 @all_detail_id         INT = NULL

AS

BEGIN

 DECLARE    @select_list        VARCHAR(4000)
 DECLARE    @where_condition    VARCHAR(4000)

 SELECT @select_list =  'SELECT DISTINCT c.table1_id, c.table1_number, c.type_id '
 SELECT @select_list = @select_list + ' FROM dbo.TABLE1 c  '
 SELECT   @select_list = @select_list + ' LEFT JOIN TABLE2 cb ON cb.table1_id = c.table2_id '
 SELECT @where_condition = ' WHERE c.active_flag = 1'
 SELECT @where_condition = @where_condition + ' AND c.type_id in 
 (select type_id from dbo.fn_get_type_ids(@category_id, @a_id, @all_detail_id)) '

END

Answer 1

您正在使用不同会话中存在的动态sql和sql变量，以使其工作，您需要将其更改为：

SELECT @where_condition = @where_condition + ' AND c.type_id in 
 (select type_id from dbo.fn_get_type_ids('+CAST(@category_id as varchar))+', 
'+CAST(@a_id as varchar))+', '+CAST(@all_detail_id as varchar))+')) '

Answer 2

尝试进行最后一次选择：

SELECT @where_condition = @where_condition + ' AND c.type_id in 
 (select type_id from dbo.fn_get_type_ids(' + ISNULL(@category_id,'NULL') + ', ' + ISNULL(@a_id,'NULL') + ', ' + ISNULL(@all_detail_id,'NULL') + ')) '

SQL查询调用用户定义的函数问题

2 个答案: