我正在制作语言翻译,而且我已经达到了我需要评估if语句的程度。起初我认为这很简单,我能够让我的解释器在这样的条件下评估简单,10 == 10
但是当我试图让它评估一个更复杂的条件时,10 == 10 and 9 > 2
例如,它搞砸了。
我制作了一些代码C ++代码,可以单独评估条件的每个部分,例如。
"Hello World" == "Hello World" or "Test" == "Test"
它目前的工作原理如下,它给出了上面的实际结果和下面的预期结果。结果如下:
TRUE or TRUE <- Actual
-----------------------
TRUE or TRUE <- Expected
-----------------------
以下是代码:
#include <iostream>
#include <string>
#include <vector>
#include "cond.h"
using namespace std;
vector <string> cond_holder;
vector <string> res;
vector <string> expects;
bool eval_cond(string cond) {
int i;
int i2;
bool state = 0;
bool final_return = false;
string c = "";
for (i = 0; i < cond.length();i++) {
c += cond[i];
if (cond[i] == '"') {
if (state == 0)
state = 1;
else
state = 0;
} else if (cond[i] == ' ' && state == 0) {
c = c.substr(0,c.length()-1);
cond_holder.push_back(c);
c = "";
}
if (i == cond.length()-1) {
cout << c << endl;
}
}
for (i = 0; i < cond_holder.size();i++) {
if (cond_holder[i+1] == "eqeq") {
expects.push_back("TRUE");
if (cond_holder[i] == cond_holder[i+2]) {
res.push_back("TRUE");
} else {
res.push_back("FALSE");
}
i+=3;
}
if (cond_holder[i] == "and") {
res.push_back("and");
expects.push_back("and");
} else if (cond_holder[i] == "or") {
res.push_back("or");
expects.push_back("or");
}
}
for (i = 0; i < res.size();i++) {
cout << res[i] << " ";
}
cout << endl << "-----------------------" << endl;
for (i = 0; i < expects.size();i++) {
cout << expects[i] << " ";
}
cout << endl << "-----------------------" << endl;
return final_return;
}
int main() {
cout << eval_cond("string:\"Hello World\" eqeq string:\"Hello World\" or string:\"H\" eqeq string:\"H\" ") << endl;
return 0;
}
老实说,我刚刚开始编写代码,所以如果有人能告诉我一个更好的方法,我会感激不尽。我甚至不确定下一步该如何使用此代码。
答案 0 :(得分:2)
Variable is an expression
Number is an expression
String is an expression
Expression == Expression is an expression
Expression AND Expression is an expression
Expression ; is a statement
IF Expression { statement } is a statement
用这样的位来构建你的语言,让它们一起崩溃。 Flex和Yacc的旧unix手册是对该主题的一个很好的介绍。