Question

目前有分钟（bigint）为

我想将此分钟转换为小时。有没有转换它的功能？

Eg: 390 as 6.30

Answer 1

这样的事情应该有效：

SELECT  TO_CHAR('390 minute'::interval, 'HH24:MI')...

回答相关问题：PostgreSQL - How to convert seconds in a numeric field to HH:MM:SS

Answer 2

您应该能够将它们转换为间隔，然后使用date_part来提取所需的字段

   select date_part('hours',interval '1 minute' * minutes) as hours,  date_part('minutes',interval '1 minute' * minutes) as minutes;

示例：

dev=# select date_part('hours',interval '1 minute' * 390) as hours, date_part('minutes',interval '1 minute' * 390) as minutes;
 hours | minutes
-------+---------
     6 |      30

编辑：回复其他评论..

select date_part('hours',interval '1 minute' * minutes) + (date_part('minutes',interval '1 minute' * minutes) * .01);

强制它为数字。

示例：

select date_part('hours',interval '1 minute' * 390) + (date_part('minutes',interval '1 minute' * 390) * .01) as foo;
 foo
-----
 6.3
(1 row)

转换为数字

select  cast(date_part('hours',interval '1 minute' * 390) * 1.0 + (date_part('minutes',interval '1 minute' * 390) * .01) as numeric(4,2))  as foo;

 foo
------
 6.30
(1 row)

或

dev=# select  cast(date_part('hours',interval '1 minute' * 240) * 1.0 + (date_part('minutes',interval '1 minute' * 240) * .01) as numeric(4,1))  as foo;
 foo
-----
 4.0
(1 row)

Answer 3

你可以拥有PostgreSQL Function，

CREATE OR REPLACE FUNCTION fn_min_to_hrs(mins int)
RETURNS numeric AS
$BODY$ 
select  cast(date_part('hours',interval '1 minute' * mins) * 1.0 + 
(date_part('minutes',interval '1 minute' * mins) * .01) as numeric(18,2));
$BODY$
LANGUAGE sql VOLATILE

select fn_min_to_hrs(390)

    Result
+-------------+
|fn_min_to_hrs|
|numeric(18,2)|
+-------------+
|        6.30 |
+-------------+

在PostgreSQL中将分钟转换为小时

3 个答案: