Question

我想映射这样的结构：

{ 
    "stuff": {
        "onetype": [
            {"id":1,"name":"John Doe"},
            {"id":2,"name":"Don Joeh"}
        ],
        "othertype": {"id":2,"company":"ACME"}
    }, 
    "otherstuff": {
        "thing": "some value"
     }
}

到包含2个对象数组的对象（东西和其他东西）。我想为这个JSON对象构建一个原型，以便我可以使用所有的函数。我希望能够做这样的事情（树是父对象）。 tree.display()其中display函数将数组视为一种类型，并调用函数显示在包含的对象上。

有一种简单的方法吗？有人能指出我如何做到这一点的例子吗？我可以使用像$.extend这样的函数吗？

这不起作用：

$(document).ready(function(){
    JSONString = '\
        {"stuff": \
            {"onetype": \
                [{"id":1,"name":"John Doe"},\
                {"id":2,"name":"Don Joeh"}],\
            "othertype": \
                {"id":2,"company":"ACME"}\
            }, \
        "otherstuff": {"thing": "some value" }\
        }';

    function Tree () {
        this.stuff = new StuffObject();
        this.otherstuff;
        this.showValue = function () {
            $("body").append(this.otherstuff.thing);
        }
    }

    function StuffObject () {
        this.onetype = new Array();
        this.othertype = new OthertypeObject();
    }

    function OthertypeObject () {
        this.id = 0;
        this.company = "unspecified";
        this.showCompany = function(){
            console.log(this.company);
        }
    }

    var firstTree = $.extend(true, new Tree, JSON.parse(JSONString));
    console.log(firstTree);
    firstTree.showValue();
    firstTree.stuff.othertype.showCompany();
});

Answer 1

如果您只想显示某个字段，可以尝试此操作，它将显示公司名称：

<script>
    alert("see this");
    JSONString = '\
        {"stuff": \
            {"onetype": \
                [{"id":1,"name":"John Doe"},\
                {"id":2,"name":"Don Joeh"}],\
            "othertype": \
                {"id":2,"company":"ACME"}\
            }, \
        "otherstuff": {"thing": "some value" }\
        }';

    function Tree () {
        this.stuff = new StuffObject();
        this.otherstuff;
        this.showValue = function () {
            $("body").append(this.otherstuff.thing);
        }
    }

    function StuffObject () {
        this.onetype = new Array();
        this.othertype = new OthertypeObject();
    }

    function OthertypeObject () {
        this.id = 0;
        this.company = "unspecified";
        this.showCompany = function(){
            console.log(this.company);
        }
    }

    var firstTree = $.extend(true, new Tree, JSON.parse(JSONString));
   // var x=json_encode(firstTree);
    console.log(firstTree);
    var x = JSON.stringify(firstTree.stuff.othertype.company);
    alert(x);

</script>

如何将嵌套的JSON映射到具有函数的Object结构？

1 个答案: