Question

我尝试使用数据类型blob。这给了一些Datastax例外。我尝试了对象本身，bytearray。仍然没有好处：

 Caused by: com.datastax.driver.core.exceptions.InvalidQueryException: Invalid STRING constant ([B@547248ad) for user_object of type blob

这是失败的INSERT：

executeSting.append("INSERT INTO htadb.objecttable (object_id, bucket_name, object_key, link, user_status, user_object) ")
            .append("VALUES (")
            .append(objectId).append(",'")
            .append(bucketName).append("','")
            .append(key).append("','")
            .append(link).append("','")
            .append("online").append("','")
            .append(serializer(register)).append("')"
                    + ";");

Answer 1

来自文档

blob  | blobs  |  Arbitrary bytes (no validation), expressed as hexadecimal

所以你需要的是Bytes课程。以下是我用来序列化/反序列化我需要在Cassandra中保存的Java对象的接口

public interface Bufferable extends Serializable {

    static final Logger LOGGER = LoggerFactory.getLogger(Bufferable.class);

    default ByteBuffer serialize() {
        try (ByteArrayOutputStream bytes = new ByteArrayOutputStream();
            ObjectOutputStream oos = new ObjectOutputStream(bytes);) {
            oos.writeObject(this);
            String hexString = Bytes.toHexString(bytes.toByteArray());
            return Bytes.fromHexString(hexString);
        } catch (IOException e) {
            LOGGER.error("Serializing bufferable object error", e);
            return null;
        }
    }

    public static Bufferable deserialize(ByteBuffer bytes) {
        String hx = Bytes.toHexString(bytes);
        ByteBuffer ex = Bytes.fromHexString(hx);
        try (ObjectInputStream ois = new ObjectInputStream(new ByteArrayInputStream(ex.array()));) {
            return (Bufferable) ois.readObject();
        } catch (ClassNotFoundException | IOException e) {
            LOGGER.error("Deserializing bufferable object error", e);
            return null;
        }
    }
}

HTH，卡罗

Answer 2

您可以使用 Array[Byte]

包装您的 java.nio.ByteBuffer.wrap() 对象

如何使用blob数据类型在cassandra中存储对象

2 个答案: