Question

我可以用这种格式获得当前月份由

val dateFormat: SimpleDateFormat = new SimpleDateFormat("YYYYMM")
dateFormat.format(new Date())//201408

但是如何获得

List(201408,201409,201410,201411,201412,201501)

Answer 1

（Java语法，但我确定你可以很容易地将它改为Scala。）

按优先顺序降序......

使用Java 8：

// TODO: Which time zone are you interested in?
YearMonth yearMonth = YearMonth.now();
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMM");
List<String> dates = new ArrayList<>();
for (int i = 0; i < 6; i++) {
    dates.add(formatter.format(yearMonth.plusMonths(i)));
}

与Joda时间：

// TODO: Which time zone are you interested in?
YearMonth yearMonth = new YearMonth();
DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyyMM");
List<String> dates = new ArrayList<>();
for (int i = 0; i < 6; i++) {
    dates.add(formatter.print(yearMonth.plusMonths(i)));
}

使用Calendar：

// TODO: Which time zone are you interested in?
Calendar calendar = Calendar.getInstance();
DateFormat format = new SimpleDateFormat("yyyyMM");
List<String> dates = new ArrayList<>();
for (int i = 0; i < 6; i++) {
    dates.add(format.format(calendar.getTime()));
    calendar.add(Calendar.MONTH, 1);
}

Answer 2

在 scala 中，使用Joda Time：

val yearMonth = new YearMonth();
val formatter = DateTimeFormat.forPattern("yyyyMM");
val dates = (0 to 5).map {
    i=>formatter.print(yearMonth.plusMonths(i)).toInt 
}.toList

即将到来的六个月的名单，包括本月

2 个答案: