Question

我的最终目标是让用户能够在活动中使用动态生成的内容（基于用户输入）在标签之间切换。我正在尝试创建一个动态布局，并将其作为片段内的布局加载。我的代码抛出错误，因为我试图提供的布局不是xml资源。我正在尝试做什么呢？

public static class JobsFragment extends Fragment{
    LinearLayout l;
        @Override
        public void onCreate(Bundle savedInstanceState)
        {
            super.onCreate(savedInstanceState);
            //set button vars here
            Log.i("aaa","called frag onCreate");
            l=new LinearLayout(getActivity());
            Button b=new Button(getActivity());
           b.setText("HI");
           l.addView(b);
    }
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,Bundle savedInstanceState) {
        Log.i("aaa","called frag onCreateView()");
        //View rootView = inflater.inflate(R.layout.fragment_section_dummy, container, false);
        View rootView = inflater.inflate(l, container, false);
        return rootView;
        }
    }
    /**
     * A {@link FragmentPagerAdapter} that returns a fragment corresponding to one of the primary
     * sections of the app.
     */
    public static class AppSectionsPagerAdapter extends FragmentPagerAdapter{

        public AppSectionsPagerAdapter(FragmentManager fm) {
            super(fm);
        }

        @Override
        public Fragment getItem(int i) {
            Fragment fragment = new JobsFragment();
            return fragment;
        }

        @Override
        public int getCount() {
            return 3;
        }

        @Override
        public CharSequence getPageTitle(int position) {
            return "Section " + (position + 1);
        }   
    }

}

Answer 1

您需要以编程方式添加布局宽度和高度。没有它，它将抛出未提供的强制布局参数的错误。添加LayoutParams是方法名称

Answer 2

使片段构造函数接受linearlayout作为参数，并使用此字段从onCreateView返回

类似于伪造的代码

  CustomFragment{
   private LinearLayout mLayout;

    CustomFragment(LinearLayout layout){
     mLayout=layout;
|   }

    onCreatView(....)
    {
     return mLayout;
    }
}

以编程方式添加创建LinearLayout作为要在片段中查看的资源

2 个答案: