我有一个如下列表。我想将列表中的数字替换为整数，该整数当前采用单引号'8'中的字符串形式。
一旦用号码替换，想要在列表中对该号码进行排序。
[['8', '/opt/sis/local/ad'], ['327912', '/opt/sis/local/bd'], ['20180', '/opt/sis/local/cd'], ['40', '/opt/sis/local/dd'], ['1464', '/opt/sis/local/ed'], ['32', '/opt/sis/local/fd'], ['3803092', '/opt/sis/local/gd'], ['34930968', '/opt/sis/local/hd'], ['3095500', '/opt/sis/local/id-inventory']]
我这样做是为了找到占用更多空间的前4个目录。
答案 0 :(得分：3)
lst = [[int(x[0]), x[1]] for x in data]
lst.sort(key=lambda x: x[0])
答案 1 :(得分：0)
首先转置它（即将行更改为列）
columns = zip(*my_2d_list)
然后更改第一列
columns[0] = [int(n) for n in columns[0]]
最后将其拉回原始列表
my_2d_list = zip(*columns)
然后只需对其进行排序
sorted(my_2d_list,reverse=True)[:4] # 4 biggest numbers ... at least it should be
sorted(my_original_list,key=lambda x: int(x[0]),reverse=True)[:4]
如@PadraicCunningham（和jon sharp）所述