CodeIgniter使用passwordHash和passwordSalt登录

Question

我的问题..变量$ salted返回一个随机的UUID然后是md5它。我需要登录才能使用变量$ salted来返回我的数据库中的passwordSalt字段的值与t1.PrincipalID = t2.UUID对应的auth表。如何给变量$ salted这个值？

基本上如何在没有用户输入的情况下从数据库中为变量赋值。谢谢。

代码片段......我的代码的重要部分。

我的观点......

<?php echo validation_errors(); ?>
<?php echo form_open('verifylogin'); ?>
<form>
    <input type="text" name="FirstName" placeholder="firstName">
    <input type="password" name="passwordHash" placeholder="Password">


    <input type="submit" name="login" class="login login-submit" value="Login">
</form></div>

我的控制员......

Function check_database($password)
{
    //Field validation succeeded.  Validate against database
    $firstName = $this->input->post('FirstName');
    $password = $this->input->post('passwordHash');




    //query the database
    $result = $this->users_model->login($firstName,$password);

    if($result)
    {
        $sess_array = array();
        foreach($result as $row)
        {
            $sess_array = array(
                'PrincipalID' => $row->PrincipalID,
                'FirstName' => $row->FirstName
            );
            $this->session->set_userdata('logged_in', $sess_array);
        }
        return TRUE;
    }
    else
    {
        $this->form_validation->set_message('check_database', 'Invalid username or password');
        return false;
    }
}

我的模特..

function login($firstName,$password)
{




     $salted  = sprintf('%s', md5(_uuid()));
     $hash = md5(md5($password) . ":" . $salted);

    $this->db->select('PrincipalID, FirstName')
        ->from('useraccounts AS t1, auth AS t2')
        ->where('t1.PrincipalID = t2.UUID')
        ->where('t1.FirstName', $firstName)
          ->where('t2.passwordHash', $hash);

    $this -> db -> limit(1);

    $query = $this -> db -> get();

    if($query -> num_rows() == 1)
    {
        return $query->result();
    }
    else
    {
        return false;
    }
}