我正在尝试在java中发送以下curl命令: 卷曲-v -XPOST -u" 7a33f0:" http://geras.1248.io/series/santander/bus3025 --header" Content-Type:application / json" -d@bus3025.json
public boolean writeSeries(String urlstr, String data){
try {
// POST
StringWriter sw = new StringWriter();
PrintWriter pw = new PrintWriter(sw);
System.out.println("POSTING");
URL url = new URL(urlstr);
String user = "7a33f0:";
String encoded = new String(Base64.encodeBase64(user.getBytes()));
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setRequestProperty("Authorization", String.format("Basic %s", encoded));
connection.setRequestProperty("Content-Type", "application/json");
connection.setRequestProperty("Accept", "*/*");
connection.setRequestProperty("Content-Length", Integer.toString(data.getBytes().length));
connection.setRequestMethod("POST");
OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream());
writer.write(data);
writer.flush();
writer.close();
int responseCode = connection.getResponseCode();
System.out.println("\nSending 'POST' request to URL : " + url);
System.out.println("Post parameters : " + data);
System.out.println("Response Code : " + responseCode);
System.out.println(connection.getContentType());
InputStream content = (InputStream) connection.getInputStream();
BufferedReader in = new BufferedReader(new InputStreamReader(
content));
String line;
while ((line = in.readLine()) != null) {
pw.println(line);
}
} catch (MalformedURLException e) {
// ...
} catch (IOException e) {
// ...
}
return true;
}
但是,我收到了401响应代码(未经授权)。
发送' POST'请求网址:http://geras.1248.io/series/santander/bus3024 发布参数:bus3024.json 回复代码:401 如何设置-u参数?谢谢你的帮助。