Question

我尝试了一个嵌套的try / except块，我想提出错误，然后从方法中断，但它会继续。

try:
    #stuff
    try:
        #do some stuff
    except:
        raise CustomException('debug info')
    #do some more stuff
except CustomException:
    #stuff
#do even more stuff
return stuff

目前，在引发CustomException（第5行）之后，它会跳转到except（第7行），然后继续并最终返回。我希望它在加注时能够突破，但不会被其他人抓住。它仍然需要捕获CustomException，如果它发生在＆＃39; #do更多东西＆＃39;并继续。

Answer 1

如何更改try-except的结构如下？

try:
    #do some stuff
except:
    raise CustomException('debug info')
try:
    #do some more stuff
except CustomException:
    #stuff
#do even more stuff
return stuff

Answer 2

只需编写raise，重新引发捕获的异常。

try:
    #stuff
    try:
        #do some stuff
    except:
        raise CustomException('debug info')
    #do some more stuff
except CustomException:
    #stuff
    raise  ## KM: This re-raise the exception

## KM: This wont be executed if CustomException('debug info') was raised
#do even more stuff

return stuff

Python在嵌套try中引发异常

2 个答案: