Question

我有一个奇怪的问题，而不是我完全不理解......

这是我的路线：

Route::get('/app/signin', array( 'as' => 'account-login', 'uses' => 'AccountController@getLogin' ));

哪个效果很好。但是，当我松开/ app部分时，我收到错误。如果我将其更改为

Route::get('/signin', array( 'as' => 'account-login', 'uses' => 'AccountController@getLogin' ));

我收到以下错误：

 * @throws \Symfony\Component\HttpKernel\Exception\HttpException
     * @throws \Symfony\Component\HttpKernel\Exception\NotFoundHttpException
     */
    public function abort($code, $message = '', array $headers = array())
    {
        if ($code == 404)
        {
            throw new NotFoundHttpException($message);
        }
        else

非常感谢任何帮助

**更新1 **

以下是我的完整路线列表：

// ALL PUBLIC ACCESS ROUTES
Route::get('/', array( 'as' => 'home', 'uses' => 'HomeController@home' ));
Route::get('/{username}', array( 'as' => 'profile-user', 'uses' => 'ProfileController@user' ));


// UNAUTHENTICATED GROUP (GUEST - PUBLIC ACCESS WITH FORMS AND SIGNUP)
Route::group(array('before' => 'csrf'), function() {

    Route::post('/app/create', array( 'as' => 'account-create-post', 'uses' => 'AccountController@postCreate' ));
    Route::post('/app/login', array( 'as' => 'account-login-post', 'uses' => 'AccountController@postLogin' ));
    Route::post('/app/forgot-password', array( 'as' => 'account-forgot-password-post', 'uses' => 'AccountController@postForgotPassword' ));

});

Route::get('/app/forgot-password', array( 'as' => 'account-forgot-password', 'uses' => 'AccountController@getForgotPassword' ));
Route::get('/app/recover{code}', array( 'as' => 'account-recover', 'uses' => 'AccountController@getRecover' ));
Route::get('/app/signin', array( 'as' => 'account-login', 'uses' => 'AccountController@getLogin' ));
Route::get('/app/create', array( 'as' => 'account-create', 'uses' => 'AccountController@getCreate' ));
Route::get('/app/activate/{code}', array( 'as' => 'account-activate', 'uses' => 'AccountController@getActivate' ));


// AUTHENTICATED GROUP (WHEN USER IS LOGGED IN)
Route::group(array('prefix' => 'app', 'before' => 'auth'), function() {

    Route::group(array('before' => 'csrf'), function() {

        Route::post('/change-password', array( 'as' => 'account-change-password-post', 'uses' => 'AccountController@postChangePassword' ));

    });

    Route::get('/change-password', array( 'as' => 'account-change-password', 'uses' => 'AccountController@getChangePassword' ));
    Route::get('/signout', array( 'as' => 'account-sign-out', 'uses' => 'AccountController@getSignOut' ));

});

Answer 1

Route::get('/{username}', array( 'as' => 'profile-user', 'uses' => 'ProfileController@user' ));

问题是，我建议澄清这条路线，先添加一些东西，或者把它放在路线的底部，这样其他定义的单字路线就会先找到它们各自的路径控制器。

建议插入正则表达式（根据需要进行修改）

Route::pattern('username', '[a-z]+')

在该路线之前

或使用像这样的where子句

Roue::get( /* username */ )->where('username', '[a-z]+');

这种方法应该用在每个路由参数上，以便更好地控制路由和数据操作。

旁注

阻止用户拥有其他单词路由的用户名，因为用户@BarryWalsh建议无法访问这些路由。

Answer 2

这看起来确实很奇怪，但作为一个开始，我试着看看是否从目标URI中删除了前面的斜线（因此'/ signin'变为'signin'）修复了问题，因为这些不是必需的。

Laravel路线迫使我使用/ double / route而不是/ single

2 个答案: