Question

我已从php5.2升级到php5.3。在此之前我的代码工作正常。升级后我得到了错误＆＃34;电子邮件已经在使用....＆＃34;虽然电子邮件不存在于数据库中。请帮忙。

<?php
$request = trim(strtolower($_REQUEST['username']));

$query = "SELECT username FROM advt WHERE username = '$username';";
$result = mysql_query($query) or die(mysql_error());
$valid = 'true';

if (mysql_num_rows($result) != 0)
    $valid= '"The email is already in use, please choose another"';
{
    echo $valid;
}
?>

Answer 1

这是PDO中的一个实现。它可能无法正常工作，因为在PHP 5.5中不推荐使用mysql函数。将dbname=test替换为您的数据库名称，并创建$user和$pass变量以使用正确的权限访问它

$username = trim(strtolower($_REQUEST['username']));
try {
    $user = 'root';
    $pass = 'password';

    $dbh = new PDO('mysql:host=localhost;dbname=test', $user, $pass);
    $stmt = $dbh->prepare("SELECT username FROM advt WHERE username = :username LIMIT 1;"); //Limit this to one result
    $stmt->bindParam(':username', $username); // bind the parameters to prevent sql injection
    $stmt->execute();

    $valid = 'true';
    //returns an array of results
    $result = $stmt->fetchAll(PDO::FETCH_ASSOC);

    //If the array is empty, no results have been returned
    if (count($result) != 0) {
        $valid = '"The email is already in use, please choose another"';
    }

    $dbh = null;
    echo $valid;

} catch (PDOException $e) {
    print "Error!: " . $e->getMessage() . "<br/>";
    die();
}

Answer 2

$ query =＆＃34; SELECT username FROM advt WHERE username = ＆＃39; {$用户名}＆＃39 ;;＆＃34 ;;

检查用户可用性

2 个答案: