Question

我有一个如下所示的文本文件：

people 0.508931508057 -0.280345656093 -0.0318199105583 -0.189979892892 0.00748802665945 -0.0570929853912 0.0688883067716 0.187604694632 0.114414087961 0.150298183734 
well 0.634085165013 -0.130742033765 0.0833007355449 -0.304469830925 0.133714906135 -0.0221626440854 0.062845160898 0.0607120405012 0.0384326647526 -0.0102762686058 
it
 0.451455675985 -0.0309283486444 -0.233415252863 -0.0273732833795 -0.294310277236 0.324236481567 -0.084486587459 0.340305398253 -0.56250445207 0.00640281538272 
but 0.776732251824 0.0216479978956 0.326422159918 0.0654654707123 0.235569019918 0.0792330670559 0.22189299375 0.194232853917 0.102964793215 0.00926554861178 
could 0.505766726467 -0.304640132821 0.015043924871 -0.42831149929 0.13475950648 0.0275223466164 0.154347034425 0.443048319277 0.229038343902 -0.209763506494 
think 0.734314690035 -0.15352368041 0.383964369466 -0.283262375383 0.000534210123265 0.0452656078196 0.0174349360274 -0.0210130687293 0.0247592836651 0.0930452272721 
movie
 0.444291696176 -0.110937149049 -0.259525377532 0.00986849685667 -0.311934727067 0.319610517473 -0.0644468651461 0.372562407 -0.572686043624 0.0262434708424 
made 0.546164908581 -0.148512160184 0.301391306124 -0.553970562504 -0.0423941756245 -0.0789194920559 -0.0336542251386 0.00929984630184 -0.030340761377 -0.112650323493 
way 0.751616772605 -0.345057880564 0.10091886809 -0.147689086912 -0.0721519520719 -0.246317313253 -0.00606560306655 0.0689594126233 0.0468387063595 -0.00900506150062

我想在文件中只保留同一行中包含单词和一组值的行。

如何删除其余部分？

预期输出为：

people 0.508931508057 -0.280345656093 -0.0318199105583 -0.189979892892 0.00748802665945 -0.0570929853912 0.0688883067716 0.187604694632 0.114414087961 0.150298183734 
well 0.634085165013 -0.130742033765 0.0833007355449 -0.304469830925 0.133714906135 -0.0221626440854 0.062845160898 0.0607120405012 0.0384326647526 -0.0102762686058 
but 0.776732251824 0.0216479978956 0.326422159918 0.0654654707123 0.235569019918 0.0792330670559 0.22189299375 0.194232853917 0.102964793215 0.00926554861178 
could 0.505766726467 -0.304640132821 0.015043924871 -0.42831149929 0.13475950648 0.0275223466164 0.154347034425 0.443048319277 0.229038343902 -0.209763506494 
think 0.734314690035 -0.15352368041 0.383964369466 -0.283262375383 0.000534210123265 0.0452656078196 0.0174349360274 -0.0210130687293 0.0247592836651 0.0930452272721 
made 0.546164908581 -0.148512160184 0.301391306124 -0.553970562504 -0.0423941756245 -0.0789194920559 -0.0336542251386 0.00929984630184 -0.030340761377 -0.112650323493 
way 0.751616772605 -0.345057880564 0.10091886809 -0.147689086912 -0.0721519520719 -0.246317313253 -0.00606560306655 0.0689594126233 0.0468387063595 -0.00900506150062

Answer 1

解决问题的几种方法。

将文件读取为CSV格式。如果列计数为12且第一列不是空字符串，请将其写出：

import csv

with open('original.txt','r') as f, open('new.txt','w') as o:
   reader = csv.reader(f, delimiter=' ')
   writer = csv.writer(o, delimiter=' ')
   for row in reader:
       if len(row) == 12 and row[0]:
           writer.write(row)

读取文件，写出第一项是单词的行，且有两列以上：

with open('original.txt', 'r') as f, open('new.txt', 'w') as o:
    for line in f:
       if line.lstrip().split(' ')[0].isalpha() and len(line.split(' ')) > 2:
           o.write(line)

Answer 2

您可以使用fileinput模块很好地实现这一点：

import fileinput
import sys

for line in fileinput.input(inplace=True):
    if line.find(' ') > 0:
        sys.stdout.write(line)

请注意，这会修改命令行上就地提供的所有文件，即它们将被修改。

Answer 3

您可以打开文件并逐行阅读。包含字母的每一行都可以复制到另一个文件中。

letters = "abcdefghijklmnopqrstuvwxyz"
letters += letters.upper()

f_in = open("myfile.txt", 'rb')
f_out = open("newfile.txt", 'wb')
for line in f_in:
    for letter in letters:
        if letter in line:
            f_out.write(line)
            break
f_in.close()
f_out.close()

注意，您给出的示例只包含一个长行。该行必须分成多行。

Answer 4

试试这个。希望这能给你带来理想的结果。

import re
f = open("i1.txt", "r")
lines = f.readlines()
new_list = []
for items in lines:
    if re.match("[a-zA-Z]+[\s\d]+", items.strip()) or re.match("[\d.\s]+[a-zA-Z]+[\s\d.]*", items.strip()):
        print items.strip()

以下是输出

people 0.508931508057 -0.280345656093 -0.0318199105583 -0.189979892892 0.00748802665945 -0.0570929853912 0.0688883067716 0.187604694632 0.114414087961 0.150298183734
well 0.634085165013 -0.130742033765 0.0833007355449 -0.304469830925 0.133714906135 -0.0221626440854 0.062845160898 0.0607120405012 0.0384326647526 -0.0102762686058
but 0.776732251824 0.0216479978956 0.326422159918 0.0654654707123 0.235569019918 0.0792330670559 0.22189299375 0.194232853917 0.102964793215 0.00926554861178
could 0.505766726467 -0.304640132821 0.015043924871 -0.42831149929 0.13475950648 0.0275223466164 0.154347034425 0.443048319277 0.229038343902 -0.209763506494
think 0.734314690035 -0.15352368041 0.383964369466 -0.283262375383 0.000534210123265 0.0452656078196 0.0174349360274 -0.0210130687293 0.0247592836651 0.0930452272721
made 0.546164908581 -0.148512160184 0.301391306124 -0.553970562504 -0.0423941756245 -0.0789194920559 -0.0336542251386 0.00929984630184 -0.030340761377 -0.112650323493
way 0.751616772605 -0.345057880564 0.10091886809 -0.147689086912 -0.0721519520719 -0.246317313253 -0.00606560306655 0.0689594126233 0.0468387063595 -0.00900506150062

0.34567是0.9876 -0.00606560306655 0.0689594126233 0.0468387063595 -0.00900506150062

如何在Python中删除文件中的行？

4 个答案: