Question

我想在另一个应用程序中打开一个应用程序的活动为此我正在做

Intent intent = new Intent();

intent.setComponent(new ComponentName("com.android.settings",
            "com.android.settings.audiopreferences.SystemAudioSettings"));

context.startActivity(intent);

如果我执行上面的Im得到以下异常

id=1: thread exiting with uncaught exception (group=0x40fac930)
E/AndroidRuntime( 2741): FATAL EXCEPTION: main
E/AndroidRuntime( 2741): java.lang.SecurityException: Permission Denial: starting Intent { cmp=com.android.settings/.audiopreferences.SystemAudioSettings } from ProcessRecord{414c0b58 2741:com.dea600.radioapp/u0a10071} (pid=2741, uid=10071) not exported from uid 1000
E/AndroidRuntime

Answer 1

android:exported="true"; // Have to include it in the manifest file - activity to be used across multiple applications
Example 

     <activity
         android:name="com.example1.utility.MainActivity"
         android:exported="true"
         android:label="@string/app_name" />

Using MAinActivity from Another application

   Intent intent = new Intent();
   intent.setClassName("com.example.utility", "com.example1.utility.MainActivity");
   context.startActivity(intent3);

Answer 2

您正在尝试从系统中打开设置活动。您将有更好的机会使用实际的＆＃34;动作＆＃34;对于那项活动。试试

context.startActivity(new Intent("android.settings.SOUND_SETTINGS"));

Answer 3

试试这个

Intent LaunchIntent = getPackageManager().getLaunchIntentForPackage("com.package.address");
startActivity(LaunchIntent);

如何在另一个应用程序中打开一个应用程序的活动

3 个答案: