使用名为＆＃39;＆＃39; PASSWORD＆＃34;的列创建表格

Question

这是我的脚本和我得到的错误。我做错了什么？

create table PHONE_USERS (
 TELEPHONE_NUMBER VARCHAR2(80)  NOT NULL, PRIMARY KEY 
 FIRST_NAME VARCHAR2(80),
 LAST_NAME VARCHAR2(80),
 KEYMAP_LASTNAME CHAR(4), 
"PASSWORD" VARCHAR2(80),
 CONSTRAINT LAST_NAME UNIQUE (TELEPNONE_NUMBER)
 );

  

命令行错误：7列：31
  错误报告 -
  SQL错误：ORA-00904：“TELEPNONE_NUMBER”：标识符无效   00904. 00000 - “％s：无效标识符”
  *原因：
  *行动：

Answer 1

TELEPNONE_NUMBER拼写错误。必须是TELEPHONE_NUMBER

create table PHONE_USERS (
 TELEPHONE_NUMBER VARCHAR2(80)  NOT NULL PRIMARY KEY, 
 FIRST_NAME VARCHAR2(80),
 LAST_NAME VARCHAR2(80),
 KEYMAP_LASTNAME CHAR(4), 
"PASSWORD" VARCHAR2(80),
 CONSTRAINT LAST_NAME UNIQUE (TELEPHONE_NUMBER)
 );

Answer 2

发生此错误，因为我认为在NOT NULL和TELEPHONE_NUMBER拼写不匹配之后放置了逗号。

将TELEPNONE_NUMBER更改为TELEPHONE_NUMBER

create table PHONE_USERS (
 TELEPHONE_NUMBER VARCHAR2(80)  NOT NULL PRIMARY KEY, 
 FIRST_NAME VARCHAR2(80),
 LAST_NAME VARCHAR2(80),
 KEYMAP_LASTNAME CHAR(4), 
"PASSWORD" VARCHAR2(80),
 CONSTRAINT LAST_NAME UNIQUE (TELEPHONE_NUMBER)
 );