Question

我想做类似的事情（所有这些代码都在模型中，自然而然）：

public $virtualFields = array(
    'description' => $this->fillDescription()
);

private function fillDescription() {
    $type = $this->data['type'];
    $quantity = $this->data['quantity'];
    switch($type) {
        case 'type A':
            'This should be a specific description for type A records and this record has quantity:'.$quantity;
            break;
        case 'type B':
            'This should be a specific description for type B records and this record has quantity:'.$quantity;
            break;
        etc...
    }
}

有什么方法在模型中执行此操作，或者我真的需要动态创建此虚拟字段？

Answer 1

您可以使用虚拟字段执行此操作：

public $virtualFields = array(
    'description' => '
      CASE 
      WHEN type = "A" THEN CONCAT("quantity a description ", quantity)
      WHEN type = "B" THEN CONCAT("quantity b description ", quantity)
      WHEN type = "C" THEN CONCAT("quantity c description ", quantity)
      END
    '
);

我不熟悉MySQL CASE，但这应该是您正在寻找的。

如果您想在模型中使用PHP，请在构建模型时执行此操作：

public function __construct($id = false, $table = null, $ds = null) {
    $this->virtualFields['description'] = $this->fillDescription();
    parent::__construct($id, $table, $ds);
}

private function fillDescription() {
     $out = 'CASE';
     $out .= ' WHEN type = "A" THEN CONCAT("quantity a description ", quantity)';
     $out .= ' WHEN type = "B" THEN CONCAT("quantity a description ", quantity)';
     $out .= ' WHEN type = "C" THEN CONCAT("quantity a description ", quantity)';
     $out .= ' END';
     return $out;
}

如果您需要针对quantity或type执行逻辑，我建议改为使用afterFind。

使用函数在CakePHP中定义虚拟字段值

1 个答案: