Question

我正在尝试仅获得已批准的回复（已暂存＆gt; 1）但由于某种原因，主要连接中的Reply.staged＆gt; 1无法正常工作

我对sqlAlchemy很新，所以我不确定父母与remote_side的关系是什么

class Story(Base):

  __tablename__ = ’Story'

  id = Column(‘ID', Integer, primary_key=True)

  anonymous = Column(TINYINT)
  detail = Column('detail',String, js_name='detail')
  summary = Column('summary',String, js_name='questionSummary')
  user_id = Column('uid', Integer, ForeignKey('rlUser.uid'), js_name='userId')
  user = relationship("User")
  inspire_id = Column('inspireID', Integer, js_name='inspireId')
  staged = Column(TINYINT)

class Reply(Base):
  __tablename__ = 'Reply'
  id = Column('replyID', Integer, primary_key=True)
  parent_id = Column('parentID', Integer, ForeignKey('rlReply.replyID'),js_name='parentId')
  user_id = Column('userID', Integer, js_name='userId')
  detail = Column(String, js_name='detail')
  reply_date = Column('replyDate', TIMESTAMP, js_name='replyDate')
  expertise_type = Column('expertiseType', Integer, js_name='expertiseType')
  status = Column(Integer)
  staged = Column(Integer)
  story = relationship(“Story",primaryjoin='and_(Reply.story_id == Story.id, Reply.parent_id==0, Reply.staged>1)', backref=backref("replies", uselist=True ))
  parent = relationship('Reply',primaryjoin='and_(Reply.parent_id==Reply.id, Reply.staged>1)', backref='responses', remote_side='Reply.id', viewonly=True, uselist=True)

  def __init__(self):
    self.staged = constants.POST_QUEUE_STATUS['STAGED']

  @property
  def reply_count(self):
    return len(self.responses)

story.replies的where子句： WHERE Reply。rushlineID =％s AND Reply。parentID =％s AND Reply。staged＆gt; ％S

parms sqlalchemy.engine.base.Engine（110L，0,1）

然而，这是完美的： story.replies [0]的where子句。响应：在哪里Reply。parentID =％s AND％s＆gt; ％S

params是sqlalchemy.engine.base.Engine（68L，2,1）

我需要的是WHERE Reply。parentID =％s AND AND Reply。staged＆gt; ％s AND％s＆gt; ％S sqlalchemy.engine.base.Engine（68L，1,2,1）

Answer 1

这个神奇的咒语，我不得不承认，我经历了试验和很多错误。以下是相关内容：

parent_id = RlColumn('parentID', Integer, ForeignKey('rlReply.replyID'), js_name='parentId')
parent = RlRelationship('Reply', primaryjoin='and_(Reply.parent_id==remote(Reply.id),Reply.flagged_status <2)',remote_side=id, uselist=True, foreign_keys=parent_id, backref='replies')

sqlalchemy与过滤器的关系

1 个答案: