Question

我需要从下面的数组中创建一个哈希，让它看起来像 - peoples_ages = {＆＃34; Joe＆＃34; =＆gt; 25}。我可以使用each_with_index迭代它，但我不需要索引作为值，我需要这个人的年龄。相反，我想要使用Hash [people_array] ...或.each_with_object。是否最好使用.map而不是之后放入.to_h？

class Person

attr_reader :name, :age

def initialize(name, age)
    @name = name
    @age = age
end
end

nick = Person.new("Nick", 25)
jim = Person.new("Jim", 37)
bob = Person.new("Bob", 23)
rob = Person.new("Rob", 29)
sue = Person.new("Sue", 31)

peeps = [nick, jim, bob, rob, sue]

# iterate over peeps array to create a hash that looks like this:
# people_ages = {
#   "Nick" => 25,
#   "Jim" => 37,
#   "Bob" => 23,
# etc...
# }

Answer 1

peeps.each_with_object({}){|e, h| h[e.name] = e.age}

Answer 2

Hash[peeps.map {|person| [person.name, person.age]} ]

或者如果Ruby 2.0

peeps.map {|person| [person.name, person.age]}.to_h

你如何迭代数组来创建哈希？

2 个答案: