Question

我有一个服务 - personService - 在我的Angular应用程序中有两个方法getEverybody和getPersonById。我可以使用sinon stub替换我的服务中的方法，如下所示：

var everybody = [...];
serviceMock= sinon.stub(personService, "getEverybody").returns(everybody);

如果我想替换这两种方法，我该怎么写？这似乎不起作用：

var everybody = [...];
var aPerson = {...};
serviceMock= sinon.stub(personService, "getEverybody").returns(everybody);
serviceMock= sinon.stub(personService, "getPersonById").returns(aPerson);

Answer 1

语法

var stub = sinon.stub(object, "method");

返回实际方法的存根，而不是整个对象。你应该写

getEverybodyStub = sinon.stub(personService, "getEverybody").returns(everybody);
getPersonByIdStub = sinon.stub(personService, "getPersonById").returns(aPerson);

然后你可以写这样的测试

describe('PersonService', function(){
  var personSrvc;
  beforeEach(inject(function (PersonService) {
      personSrvc= PersonService;
  }));

  it('should return all persons', function(){
      var everybody = [{name:'aaa'}, {name:'bbb'}];
      var getEverybodyStub = sinon.stub(personSrvc,"getEverybody").returns(everybody);
      var allPersons = personSrvc.getEverybody();
      expect(allPersons ).toEqual(everybody );
      expect(getEverybodyStub.called).toBe(true);
  });
});

替换sinon存根中的多个方法

1 个答案: