Question

我试图插入两行，但每行的ID都在同一个数组中，如何正确插入？

因为我试过这种方式但只插入第一个id。

$sql = "
    INSERT INTO cars(car, price, createdDate, createdBy) 
    VALUES (".$this->db->escape($ids).",
            ".$this->db->escape($price).",
            NOW(),
            ".$this->session->userdata('admin_id').")";             

    mysql_query($sql);
    echo ($sql);

这就是我得到的：

INSERT INTO cars (car, price, createdDate, createdBy) 
VALUES ('217450,217449', '15', NOW(), 150)

在车里，我想在两辆车216450,217449上插入价格，createdDate和createdBy。

提前谢谢。

Answer 1

使用PHP函数explode：

$ids= explode(',', $ids);
foreach($ids as $id)
{
    $sql = "INSERT INTO cars(car, price, createdDate, createdBy) 
        VALUES (" . $this->db->escape($id) . ", " . $this->db->escape($price)
        . ", NOW(), " . $this->session->userdata('admin_id') . ")";
    mysql_query($sql);
}

Answer 2

$ids = "217450, 217449";
$id_explode = explode(",", $ids);

foreach($id_explode as $id)
{
    $sql = "
             INSERT INTO cars(car, price, createdDate, createdBy) 
             VALUES (".$this->db->escape($id).",
             ".$this->db->escape($price).",
             NOW(),
             ".$this->session->userdata('admin_id').")
           ";             

   mysql_query($sql);
   echo ($sql);
}

但我建议您不要使用原始SQL查询，因为容易受到SQL注入。
因此，使用CI＆＃39; s active record ：

$ids = "217450, 217449";
$id_explode = explode(",", $ids);

$insert_batch = array();
foreach($id_explode as $id)
{
    $arr = array(
              'car' => $id,
              'price' => $price,
              'createdDate' => NOW(),
              'createdBy' => $this->session->userdata('admin_id'),
             );
    $insert_batch[] = $arr;
}

$this->db->insert_batch('cars', $insert_batch);

的文档：

https://ellislab.com/codeigniter/user-guide/database/active_record.html

Answer 3

如果你使用id作为数组 $ ids = array（'217450'，'217449'）;

$sql = "
INSERT INTO cars(car, price, createdDate, createdBy) 
VALUES ";
foreach($ids as $id){

$sql .=(".$this->db->escape($id).",
        ".$this->db->escape($price).",
        NOW(),
        ".$this->session->userdata('admin_id')."),";             
}
mysql_query($sql);
echo ($sql);

现在它将创建查询

 INSERT INTO cars (car, price, createdDate, createdBy)
VALUES ('217450', '15', NOW(), 150),('217450', '15', NOW(), 150);

在Codeigniter中插入Ids数组

3 个答案: