获取Moment Js中两个日期之间的小时差异

Question

我能够使用MomentJs获得两个日期之间的差异，如下所示：

moment(end.diff(startTime)).format("m[m] s[s]")

但是，我也想在适用的时候显示小时（仅当＆gt; = 60分钟过去时）。

但是，当我尝试使用以下内容检索持续时间时：

var duration = moment.duration(end.diff(startTime));
var hours = duration.hours();

它返回当前小时而不是两个日期之间的小时数。

如何获得两个时刻之间的小时差异？

Answer 1

你很亲密。您只需使用duration.asHours()方法（请参阅the docs）。

var duration = moment.duration(end.diff(startTime));
var hours = duration.asHours();

Answer 2

以下代码块显示了如何使用MomentJS计算两个日期之间的天数差异。

var now = moment(new Date()); //todays date
var end = moment("2015-12-1"); // another date
var duration = moment.duration(now.diff(end));
var days = duration.asDays();
console.log(days)

Answer 3

或者你可以做到：

var a = moment('2016-06-06T21:03:55');//now
var b = moment('2016-05-06T20:03:55');

console.log(a.diff(b, 'minutes')) // 44700
console.log(a.diff(b, 'hours')) // 745
console.log(a.diff(b, 'days')) // 31
console.log(a.diff(b, 'weeks')) // 4

docs：here

Answer 4

您需要做的就是将hours作为第二个参数传递给时差函数。

var a = moment([21,30,00], "HH:mm:ss")
var b = moment([09,30,00], "HH:mm:ss")
a.diff(b, 'hours') // 12

文档： https://momentjs.com/docs/#/displaying/difference/

示例：

＆＃13;

＆＃13;

const dateFormat = "YYYY-MM-DD HH:mm:ss";
// Get your start and end date/times
const rightNow = moment().format(dateFormat);
const thisTimeYesterday = moment().subtract(1, 'days').format(dateFormat);
// pass in hours as the second parameter to the diff function
const differenceInHours = moment(rightNow).diff(thisTimeYesterday, 'hours');

console.log(`${differenceInHours} hours have passed since this time yesterday`);

＆＃13;

<script 
  src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.20.1/moment.min.js">
</script>

＆＃13;

＆＃13;

＆＃13;

Answer 5

有一个很棒的moment方法，称为fromNow()，它会以一种易于理解的形式从特定时间返回时间，例如：

moment('2019-04-30T07:30:53.000Z').fromNow() // an hour ago || a day ago || 10 days ago

或者，如果您希望在两个特定日期之间使用，请使用：

var a = moment([2007, 0, 28]);
var b = moment([2007, 0, 29]);
a.from(b); // "a day ago"

来自文档：

• fromNow()
• from()

Answer 6

var __startTime = moment("2016-06-06T09:00").format();
var __endTime = moment("2016-06-06T21:00").format();

var __duration = moment.duration(moment(__endTime).diff(__startTime));
var __hours = __duration.asHours();
console.log(__hours);

Answer 7

 var start=moment(1541243900000);
 var end=moment(1541243942882);
 var duration = moment.duration(end.diff(startTime));
 var hours = duration.asHours();

如您所见，开始和结束日期必须是此方法起作用的时刻对象。

Answer 8

我知道这很旧，但这是一个单一的解决方案：

const hourDiff = start.diff(end, "hours");

开始和结束是力矩对象。

享受！

Answer 9

根据 Moment JS 的新弃用警告

您需要传递开始和结束日期格式的格式以及值，例如：

   let trackStartTime = "2020-12-29 09:59:19.07 +05:30";
   let trackEndTime = "2020-12-29 11:04:19.07 +05:30" || moment().format("YYYY-MM-DD HH:mm:ss.SS Z");
   let overallActivity = moment.duration(moment(trackEndTime, 'YYYY-MM-DD HH:mm:ss.SS Z').diff(moment(trackStartTime, 'YYYY-MM-DD HH:mm:ss.SS Z'))).asHours();

Answer 10

如果您希望按日计算两个日期之间的总分钟数，则下面的代码可能会对您有所帮助开始日期：2018-05-04 02:08:05 ，结束日期： 2018-05-14 09:04:07 ...

function countDaysAndTimes(startDate,endDate){
return new Promise(function (resolve, reject) {
var dayObj = new Object;
var finalArray = new Array;

var datetime1 = moment(startDate);
var datetime2 = moment(endDate);
if(datetime1.format('D') != datetime2.format('D') || datetime1.format('M') != datetime2.format('M') ||  datetime1.format('YYYY') != datetime2.format('YYYY')){
  var onlyDate1 = startDate.split(" ");
  var onlyDate2 = endDate.split(" ");
  var totalDays = moment(onlyDate2[0]).diff(moment(onlyDate1[0]), 'days')

  // First Day Entry
  dayObj.startDate = startDate;
  dayObj.endDate = moment(onlyDate1[0]).add(1, 'day').format('YYYY-MM-DD')+" 00:00:00";
  dayObj.minutes = moment(dayObj.endDate).diff(moment(dayObj.startDate), 'minutes');
  finalArray.push(dayObj);

  // Between Days Entry
  var i = 1;
  if(totalDays > 1){
    for(i=1; i<totalDays; i++){
      var dayObj1 = new Object;
      dayObj1.startDate = moment(onlyDate1[0]).add(i, 'day').format('YYYY-MM-DD')+" 00:00:00";
      dayObj1.endDate = moment(onlyDate1[0]).add(i+1, 'day').format('YYYY-MM-DD')+" 00:00:00";
      dayObj1.minutes = moment(dayObj1.endDate).diff(moment(dayObj1.startDate), 'minutes');
      finalArray.push(dayObj1);
    }
  }

  // Last Day Entry
  var dayObj2 = new Object;
  dayObj2.startDate = moment(onlyDate1[0]).add(i, 'day').format('YYYY-MM-DD')+" 00:00:00";
  dayObj2.endDate = endDate ;
  dayObj2.minutes = moment(dayObj2.endDate).diff(moment(dayObj2.startDate), 'minutes');
  finalArray.push(dayObj2);

}
else{
  dayObj.startDate = startDate;
  dayObj.endDate = endDate;
  dayObj.minutes = datetime2.diff(datetime1, 'minutes');
  finalArray.push(dayObj);
}
console.log(JSON.stringify(finalArray));
// console.table(finalArray);
resolve(finalArray);
});
}

  

输出

 [
  {
  "startDate":"2018-05-04 02:08:05",
  "endDate":"2018-05-05 00:00:00",
  "minutes":1311
  },
  {
  "startDate":"2018-05-05 00:00:00",
  "endDate":"2018-05-06 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-06 00:00:00",
  "endDate":"2018-05-07 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-07 00:00:00",
  "endDate":"2018-05-08 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-08 00:00:00",
  "endDate":"2018-05-09 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-09 00:00:00",
  "endDate":"2018-05-10 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-10 00:00:00",
  "endDate":"2018-05-11 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-11 00:00:00",
  "endDate":"2018-05-12 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-12 00:00:00",
  "endDate":"2018-05-13 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-13 00:00:00",
  "endDate":"2018-05-14 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-14 00:00:00",
  "endDate":"2018-05-14 09:04:07",
  "minutes":544
  }
 ]

Answer 11

就我而言，我想要几个小时和几分钟：

var duration = moment.duration(end.diff(startTime));
var hours = duration.hours(); //hours instead of asHours
var minutes = duration.minutes(); //minutes instead of asMinutes

有关更多信息，请参阅官方docs。

Answer 12

我知道已经回答了这个问题，但是如果您想要递归和更通用的内容，而不依赖时刻fromNow，则可以使用我创建的此函数。当然，您可以更改其逻辑以根据需要进行调整，以支持数年和数秒。

var createdAt = moment('2019-05-13T14:23:00.607Z');
var expiresAt = moment('2019-05-14T14:23:00.563Z');

// You can also add years in the beginning of the array or seconds in its end
const UNITS = ["months", "weeks", "days", "hours", "minutes"]
function getValidFor (createdAt, expiresAt, unit = 'months') {
    const validForUnit = expiresAt.diff(createdAt, unit);
    // you could adjust the if to your needs 
    if (validForUnit > 1 || unit === "minutes") {
    return [validForUnit, unit];
  }
  return getValidFor(createdAt, expiresAt, UNITS[UNITS.indexOf(unit) + 1]);
}

Answer 13

            var timecompare = {
            tstr: "",
            get: function (current_time, startTime, endTime) {
                this.tstr = "";
                var s = current_time.split(":"), t1 = tm1.split(":"), t2 = tm2.split(":"), t1s = Number(t1[0]), t1d = Number(t1[1]), t2s = Number(t2[0]), t2d = Number(t2[1]);

                if (t1s < t2s) {
                    this.t(t1s, t2s);
                }

                if (t1s > t2s) {
                    this.t(t1s, 23);
                    this.t(0, t2s);
                }

                var saat_dk = Number(s[1]);

                if (s[0] == tm1.substring(0, 2) && saat_dk >= t1d)
                    return true;
                if (s[0] == tm2.substring(0, 2) && saat_dk <= t2d)
                    return true;
                if (this.tstr.indexOf(s[0]) != 1 && this.tstr.indexOf(s[0]) != -1 && !(this.tstr.indexOf(s[0]) == this.tstr.length - 2))
                    return true;

                return false;

            },
            t: function (ii, brk) {
                for (var i = 0; i <= 23; i++) {
                    if (i < ii)
                        continue;
                    var s = (i < 10) ? "0" + i : i + "";
                    this.tstr += "," + s;
                    if (brk == i)
                        break;
                }
            }};